Equals with the number of number electrons and directly influence the mass number
Answer:
38.4 atm
Explanation:
Data obtained from the question include:
V1 (initial volume) = 3200 L
P1 (initial pressure) = 3.00 atm
V2 (final volume) = 250.0 L
P2 (final pressure) = ?
Using Boyle's law equation P1V1 = P2V2, the final pressure can be obtained as follow:
P1V1 = P2V2
3 x 3200 = P2 x 250
Divide both side by 250
P2 = 3 x 3200/250
P2 = 38.4 atm
Therefore, the pressure of the gas if ethylene is supplied by a 250.0 L tank is 38.4 atm
Beaker 3 shows a clear chemical reaction.
Explanation:
Mole ratio of Ethane to Oxygen = 2 : 7
Moles of O2 needed = 24 moles * (7/2) = 84 moles.
