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FinnZ [79.3K]
3 years ago
13

Light of wavelength 575 nm passes through a double-slit and the third order bright fringe is seen at an angle of 6.5^degree away

from the central fringe. What is the separation between the double slits? a) 5.0 mu m b) 10 mu m c) 15 mu m d) 20 mu m e) 25 mu m
Physics
1 answer:
Anon25 [30]3 years ago
4 0

Answer:

The correct option is C

Explanation:

From the question we are told that

   The wavelength is  \lambda  =  575 *10^{-9} \  m

    The  angle is  \theta  =  6.5^o

    The order of maxima  is  n =  3

Generally for  constructive interference

       dsin \theta  =  n  *  \lambda

=>   d =  \frac{n  *  \lambda }{  sin \theta }

=>   d =  \frac{3   *  575 *10^{-9} }{  sin 6.5  }

=>   d = 15.24 *10^{-6} \  m

=>  d = 15 \mu  m

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Unpolarized light of intensity I0 = 950 W/m2 is incident upon two polarizers. The first has its polarizing axis vertical, and th
Ket [755]

Answer:

Intensity of the light (first polarizer) (I₁) = 425 W/m²

Intensity of the light (second polarizer) (I₂) = 75.905 W/m²

Explanation:

Given:

Unpolarized light of intensity (I₀) = 950 W/m²

θ = 65°

Find:

a. Intensity of the light (first polarizer)

b. Intensity of the light (second polarizer)

Computation:

a. Intensity of the light (first polarizer)

Intensity of the light (first polarizer) (I₁) = I₀ / 2

Intensity of the light (first polarizer) (I₁) = 950 / 2

Intensity of the light (first polarizer) (I₁) = 425 W/m²

b. Intensity of the light (second polarizer)

Intensity of the light (second polarizer) (I₂) = (I₁)cos²θ

Intensity of the light (second polarizer) (I₂) = (425)(0.1786)

Intensity of the light (second polarizer) (I₂) = 75.905 W/m²

5 0
3 years ago
Suppose A=BnCm, where A has dimensions LT, B has dimensions L2T-1, and C has dimensions LT2. Then the exponents n and m have the
julsineya [31]

Explanation:

The expression is :

A=B^nC^m

A =[LT], B=[L²T⁻¹], C=[LT²]

Using dimensional of A, B and C in above formula. So,

A=B^nC^m\\\\\ [LT]=[L^2T^{-1}]^n[LT^2}]^m\\\\\ [LT]=L^{2n}T^{-n}L^mT^{2m}\\\\\ [LT]=L^{2n+m}T^{2m-n}

Comparing the powers both sides,

2n+m=1 ...(1)

2m-n=1 ...(2)

Now, solving equation (1) and (2) we get :

n=\dfrac{1}{5}\\\\m=\dfrac{3}{5}

Hence, the correct option is (E).

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3 years ago
What determines the path that an object in projectile motion follows
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x(t)=2 \cos (10 t)
The velocity is the derivative of the position:
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