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4 years ago

An object starts from rest and accelerates to a velocity of 10 m/s, east in 5 seconds. What is the acceleration of the object?

Physics

1 answer:

Shalnov [3]4 years ago

3 0

Answer:

2m/s²

Explanation:

acceleration is the rate of change of velocity

for velocity to reach 10m/s in 5s,

acceleration= 10/5

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Distance Using Hubble's Law II.Find the percent difference (% = |A-O|/A × 100) between the actual (A) distance values and calcul

wlad13 [49]

Answer:

Explanation:

Let us first calculate for Virgo

$A= d_{virgo} = 17;M_{pc}, V_{virgo} = 1200 km/s,
$

Using Hubble's law

$v = H_{0}D$ For Virgo

$V_{virgo} = H_{0}D_{virgo}$

$O = D_{virgo} = \frac{v_{virgo}}{H_{0}} = \frac{1200 km/s}{70 km/s/Mpc}= 17.143 Mpc
$

Percentage difference for the Virgo

$\% = \frac{|A-O|}{A}\times 100 = \frac{|17 Mpc-17.143 Mpc|}{17 Mpc}\times 100 = 0.84 \%
$

Now for calculate for Corona Borealis

$A= d_{Corona Borealis} = 310 Mpc, v_{Corona Borealis} = 22000 km/s,
$

Using Hubble's law

$v = H_{0}D$ For Corona Borealis

$v_{Corona Borealis } = H_{0}D_{Corona Borealis }
\\O = D_{Corona Borealis } = \frac{v_{Corona Borealis }}{H_{0}} = \frac{22000 km/s}{70 km/s/Mpc}= 314.286 Mpc
$

Percentage difference for the Virgo

$\% = \frac{|A-O|}{A}\times 100 = \frac{|310 Mpc-314.286 Mpc|}{310 Mpc}\times 100 = 1.3825 \%
$

So clearly Hubble's law is more accurate for the closer objects

3 0

3 years ago

1. A student is biking to school. She travels 0.7 km north, then realizes something has fallen out of her bag.

Snezhnost [94]

Explanation:

(a) Displacement of an object is the shortest path covered by it.

In this problem, a student is biking to school. She travels 0.7 km north, then realizes something has fallen out of her bag. She travels 0.3 km south to retrieve her item. She then travels 0.4 mi north to arrive at school.

0.4 miles = 0.64 km

displacement = 0.7-0.3+0.64 = 1.04 km

(b) Average velocity = total displacement/total time

t = 15 min = 0.25 hour

$v=\dfrac{1.04\ km}{0.25\ h}\\\\v=4.16\ km/h$

Hence, this is the required solution.

8 0

4 years ago

The magnetic field at the earth's surface can vary in response to solar activity. During one intense solar storm, the vertical c

Natalka [10]

Answer:

$EMF = 1684.67 Volts$

Explanation:

As we know that EMF is induced in a closed conducting loop if the flux linked with the loop is changing with time

So we can say

$EMF = \frac{d\phi}{dt}$

now we have

$\phi = BA$

here since magnetic field is constant so we have

$EMF = A\frac{dB}{dt}$

now we have

$A = (190 \times 10^3)(190 \times 10^3)$

$A = 3.61 \times 10^{10} m^2$

now we have

$EMF = 3.61\times 10^{10} (\frac{2.8 \times 10^{-6}T}{60 s})$

$EMF = 1684.67 Volts$

6 0

3 years ago

Apart from physical factors, what other environmental factors are in your environment?

lora16 [44]

Answer:

Explanation:

Factors which affects and impacts our environment may include water, sunlight, buildings and so many other. The factors which can touched are called the physical factors. The physical factirs include buildings, humans and so on. Other factirs which aren't physical inckide the the effects posed to the environment t by biological and chemical factirs which may include, the impacts in sunlight and Rainfall, the pH and so on.

5 0

3 years ago

If you were traveling 60 mph and not wearing a seatbelt and collided with a fixed object, how fast would you be traveling when y

Readme [11.4K]

Your speed when your car hits a fixed object is 60 mph.

The given parameters:

Your initial speed, v = 60 mph

<h3>What is relative velocity?</h3>

Relative velocity tells us how fast we are traveling from a fixed point or reference point.

When travel at 60 mph in a car, you are moving at the same rate with the car.

If you are not wearing a seat belt, when you hit a fixed object, you will move forward at the same rate as the car's speed.

Thus, we can conclude that your speed when your car hits a fixed object is 60 mph.

Learn more about relative velocity here: brainly.com/question/17228388

5 0

3 years ago