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mars1129 [50]
3 years ago
5

How would technology affect the population growth rate?

Chemistry
2 answers:
Rasek [7]3 years ago
8 0
B. It would lead to rapid population increase with high birth rates and low death rates due to the medical advancements
nexus9112 [7]3 years ago
6 0

Answer:

B. It would lead to rapid population increase with high birthrates and lower death rates.

Explanation:

Technology will increase birth rate and decrease death rate. Advancement in medical care allows better prenatal care, facilitates intensive care for children born with critical diseases, improved medications and baby food is also critical in saving the life of babies born. Also several vaccinations are available to prevent children from succumbing to life threatening diseases. In vitro fertilization is facilitating birth rates.  

Additionally, better healthcare facilities are available at old age such as stem cell therapy, early diagnosis of cancer, treatment for Alzheimer’s and more.  

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Which metal will gain heat faster. Brass or Gold?
FinnZ [79.3K]
Hey!!

here is your answer >>>

In order to find out which metal gains heat faster, we will have to find out their specific heat!. Specific heat is the heat required to raise the temperature of the unit substance, The specific heat of gold and brass are 0.126 for gold and 0.380 for brass!. The specific heat of gold is less than brass!. So, gold will gain heat faster!.

Hope my answer helps!
5 0
3 years ago
Read 2 more answers
Complete the sentences about heme. Some terms will not be used. The prosthetic group of hemoglobin and myoglobin is . The organi
nevsk [136]

Explanation:

Haemoglobin consists of heme unit which is comprised of an <u>Fe^{2+}</u> and porphyrin ring. The ring has four pyrrole molecules which are linked to the iron ion. In oxyhaemoglobin, the iron has coordinates with four nitrogen atoms and one to the F8 histidine residue and the sixth one to the oxygen. In deoxyhaemoglobin, the ion is displaced out of the ring by 0.4 Å.

The prosthetic group of hemoglobin and myoglobin is - <u>Heme</u>

The organic ring component of heme is - <u>Porphyrin</u>

Under normal conditions, the central atom of heme is - <u>Fe^{2+}</u>

In <u>deoxyhemoglobin</u> , the central iron atom is displaced 0.4 Å out of the plane of the porphyrin ring system.

The central atom has <u>six</u> bonds: <u>four</u> to nitrogen atoms in the porphyrin, one to a <u>histidine</u> residue, and one to oxygen.

7 0
3 years ago
Do you know how to do this? if you have 4 grams of carbon-14, how much carbon 14 remains after 11,460 years? the half life is 5,
Delvig [45]
Carbon dating has<span> given archeologists a more accurate method by which they </span>can<span> determine the age of ancient artifacts. The </span>halflife<span> of </span>carbon 14<span> is </span>5730<span> ± 30 </span>years<span>, and the method of dating lies in trying to determine how </span>much carbon 14<span> (</span><span>the radioactive isotope of carbon) is present in the artifact and comparing it to levels</span>
6 0
3 years ago
1. Write the balanced equation for the breakdown of hydrogen peroxide. The equation has been written, you just have to balance.
o-na [289]
The balanced equation is attached in the image below. The coefficients are 2, 2, blank.

7 0
3 years ago
Read 2 more answers
A 13 g sample of P4010 contains how many
Alex777 [14]

Answer:

\large \boxed{5.5 \times 10^{22}\text{ molecules of P$_{2}$O}_{5}}

Explanation:

You must calculate the moles of P₄O₁₀, convert to moles of P₂O₅,  then convert to molecules of P₂O₅.

1. Moles of P₄O₁₀

\text{Moles of P$_{4}$O}_{10} = \text{13 g P$_{4}$O}_{10} \times \dfrac{\text{1 mol P$_{4}$O}_{10}}{\text{283.89 g P$_{4}$O}_{10}} = \text{0.0458 mol P$_{4}$O}_{10}

2. Moles of P₂O₅

P₄O₁₀ ⟶ 2P₂O₅

The molar ratio is 2 mol P₂O₅:1 mol P₄O₁₀

\text{Moles of P$_{2}$O}_{5} = \text{0.0458 mol P$_{4}$O}_{10} \times \dfrac{\text{2 mol P$_{2}$O}_{5}}{\text{1 mol P$_{4}$O}_{10}} = \text{0.0916 mol P$_{2}$O}_{5}

3. Molecules of P₂O₅

\text{No. of molecules} = \text{0.0916 mol P$_{2}$O}_{5} \times \dfrac{6.022 \times 10^{23}\text{ molecules P$_{2}$O}_{5}}{\text{1 mol P$_{2}$O}_{5}}\\\\= \mathbf{5.5 \times 10^{22}}\textbf{ molecules P$_{2}$O}_{5}\\\text{There are $\large \boxed{\mathbf{5.5 \times 10^{22}}\textbf{ molecules of P$_{2}$O}_{5}}$}

6 0
3 years ago
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