Answer:
C.
Explanation:
We are given that
Initial concentration, ![[A]_o=4.3 M](https://tex.z-dn.net/?f=%5BA%5D_o%3D4.3%20M)
First half life,
minutes
Second half life,
minutes
We have to find K.
The given reaction is zero order reaction.
We know that for zero order reaction
![t_{\frac{1}{2}}=\frac{[A]_o}{2k}](https://tex.z-dn.net/?f=t_%7B%5Cfrac%7B1%7D%7B2%7D%7D%3D%5Cfrac%7B%5BA%5D_o%7D%7B2k%7D)
Using the formula



Hence, option C is correct.
What is it that you’re asking for?
Answer:
571.81 mL
Explanation:
Assuming constant pressure, we can solve this problem by using <em>Charles' law</em>, which states that at constant pressure:
Where in this case:
We <u>input the data</u>:
- 852 mL * 200 K = V₂ * 298 K
And <u>solve for V₂</u>:
The new volume would be 571.81 mL.
Take the molality and multiply it by the Kb
0.75 × 0.52 = 0.39 C
then add the boiling pt to the 0.39
100 + 0.39 = 100.39 C
Answer:
B 2
Explanation:
I checked it and it’s right hope this helps!!