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kotegsom [21]
4 years ago
6

Identify the two principal products of the reaction between ammonia and ethyl propionate

Chemistry
1 answer:
Elanso [62]4 years ago
4 0

Answer:

Ethyl propionate reacts with ammonia it gives ethanamide and ethanol.

Explanation:

When an ester reacts with ammonia to give acid amide and an alcohol. This can be expressed in the form of chemical reaction :

R-(CO)-OR'+NH_3\rightarrow R-(CO)-NH_2+R'OH

Ethyl propionate is an ethyl ester of propionic acid.

Ethyl propionate = CH_3-CH_2(CO)-OCH_2CH_3

So, when ethyl propionate reacts with ammonia it gives ethanamide and ethanol.

CH_3-CH_2(CO)-OCH_2CH_3+NH_3\rightarrow

   CH_3-CH_2-(CO)-NH_2+CH_3-CH_2-OH

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const2013 [10]
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Homogenous mixtures are evenly mixed throughout. Like salt water or kool-aid (when it's mixed).

Hope this helps!
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For a particular reaction, Δ=−111.4 kJ and Δ=−25.0 J/K.
vichka [17]

Answer:

\Delta G =-103.95kJ

Explanation:

Hello there!

In this case, since the thermodynamic definition of the Gibbs free energy for a change process is:

\Delta G =\Delta H-T\Delta S

It is possible to plug in the given H, T and S with consistent units, to obtain the correct G as shown below:

\Delta G =-111.4kJ-(298K)(-25.0\frac{J}{K}*\frac{1kJ}{1000J} )\\\\\Delta G =-103.95kJ

Best regards!

6 0
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PLZ HELP OR WILL FAIL!!
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