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Vlada [557]
3 years ago
13

Study this chemical reaction: (aq)(s)(s)(aq) Then, write balanced half-reactions describing the oxidation and reduction that hap

pen in this reaction.
a. oxidation
b. reduction:
Chemistry
1 answer:
disa [49]3 years ago
6 0

The question is incomplete, complete question is:

Study this chemical reaction:

FeSO_4 (aq) + Zn (s)\rightarrow Fe (s) + ZnSO_4 (aq)

Then, write balanced half-reactions describing the oxidation and reduction that happen in this reaction.

Oxidation:

Reduction:

Answer:

Oxidation taking place in given reaction :

Zn(s)\rightarrow Zn^{2+}+2e^-

Reduction taking place in given reaction;

Fe^{2+}(aq)+2e^-\rightarrow Fe(s)

Explanation:

Redox reaction is defined as the reaction in which oxidation and reduction reaction occur side by side.

Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

X\rightarrow X^{n+}+ne^-

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

X^{n+}+ne^-\rightarrow X

FeSO_4 (aq) + Zn (s) \rightarrow Fe (s) + ZnSO_4 (aq)

In the given reaction, iron(II) ions are getting reduced and zinc metal is getting oxidized to zinc(II) ions.

Oxidation :

Zn(s)\rightarrow Zn^{2+}+2e^-

Reduction ;

Fe^{2+}(aq)+2e^-\rightarrow Fe(s)

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A researcher recorder that a chemical reaction require 2.90 gal water and raised the temperature of the reaction vessel by 57°F.
Ivan

Answer:

10.875L

Explanation:

The problem here is a simple conversion. The conversion is from gal to liters Liter is a SI unit for recording volume as stated in the problem.

Given that:

              1 gallon of water = 3.75L

              2.90 gallon will be 2.9 x 3.75; 10.875L

4 0
3 years ago
GIVING BRAINIEST FIVE STARS AND HEART! '
son4ous [18]

Answer:

Above pH 8.3, a blue litmus paper stays blue but turns red in an acid. A neutral solution, or one between the upper and lower values of litmus paper, pH 4.5 and 8.3, will not change the paper's color

Explanation:

3 0
3 years ago
Read 2 more answers
A sample of a compound made entirely from copper and oxygen was found to have a total mass of 0.143 g the mass of copper in the
tensa zangetsu [6.8K]

Mass of Oxygen: 0.0159 grams

Moles of Oxygen: 9.94x10^-4

To find the mass of oxygen, subtract the mass of copper from the total mass.

0.143-0.1271=0.0159

There are 0.0159 grams of Oxygen.

To find how many moles there are, divide the given amount of oxygen by the molar mass (atomic mass) of oxygen because that mass is the same as one mole of oxygen.

Molar mass of Oxygen: 16.00

0.0159/16.00=9.94*10^{-4}

There are 9.94*10^-4 moles of Oxygen.

6 0
1 year ago
Does the sound wave above experience a change in pitch or loudness? Why?
Basile [38]

My Apoligies for not being sooner.

Answer: The closer the particles get or the further apart they get, the greater the sound's amplitude. Sound amplitude causes a sound's loudness and intensity. The bigger the amplitude is, the louder and more intense the sound. - (This is copied)

General Answer : Its a change in sound, bassically the bigger the waves are, the louder the sound is.

4 0
2 years ago
Radium decays to form radon. Which equation correctly describes this decay? Superscript 226 Subscript 88 Baseline Upper R a righ
KiRa [710]

Answer: 226 Subscript 88 Baseline Upper R a right arrow Superscript 222 Subscript 86 Baseline Upper R n + Superscript 4 Subscript 2 Baseline Upper H e

Explanation:

Alpha decay : When a larger nuclei decays into smaller nuclei by releasing alpha particle. In this process, the mass number and atomic number is reduced by 4 and 2 units respectively.

The general representation of alpha decay reaction is:

^{A}_{Z}\textrm{X}\rightarrow ^{A-4}_{Z-2}\textrm {Rn}+ ^{4}_{2}\textrm{He}

Representation of Radium decays to form Radon

^{226}_{88}\textrm{Ra}\rightarrow ^{222}_{86}\textrm {Rn}+ ^{4}_{2}\textrm{He}

Thus 226 Subscript 88 Baseline Upper R a right arrow Superscript 222 Subscript 86 Baseline Upper R n + Superscript 4 Subscript 2 Baseline Upper H e represents alpha decay.

         

4 0
3 years ago
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