Lighter molecules move fast and escape from the upper atmosphere relatively quickly.
To find the answer, we have to know more about the lighter isotopes.
<h3>
What are lighter isotopes?</h3>
- Lighter molecules are mobile and soon leave the higher atmosphere.
- A particular element's stable isotopes have slightly different atomic masses and quantum mechanical energies.
- The lighter isotope of an element's chemical bonds are more easily broken than the heavier isotope's.
- As a result, the light isotope typically benefits from chemical reactions.
Thus, we can conclude that, lighter molecules move fast and escape from the upper atmosphere relatively quickly.
Learn more about the isotopes here:
brainly.com/question/364529
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Momentum = Mass × Velocity
According to this formula,
Momentum of deer = 176 × 19 = 3344 kg•m/s.
Since you are heading north and the deer is running towards you, the direction of the deer' s momentum is north as well.
Answer:
h=15.27m
Explanation:
Since at maximum height the vertical velocity must be null it's better to use the formula:
![v_f^2=v_i^2+2ad](https://tex.z-dn.net/?f=v_f%5E2%3Dv_i%5E2%2B2ad)
We will use this formula for the vertical direction, choosing the upward direction as the positive one, so we have:
![0=v_i^2+2ah](https://tex.z-dn.net/?f=0%3Dv_i%5E2%2B2ah)
or
![h=-\frac{v_i^2}{2a}](https://tex.z-dn.net/?f=h%3D-%5Cfrac%7Bv_i%5E2%7D%7B2a%7D)
which for our values is:
![h=-\frac{(17.3m/s)^2}{2(-9.8m/s^2)}=15.27m](https://tex.z-dn.net/?f=h%3D-%5Cfrac%7B%2817.3m%2Fs%29%5E2%7D%7B2%28-9.8m%2Fs%5E2%29%7D%3D15.27m)
Answer:
Explanation:
Given
diameter of spacecraft ![d=148\ m](https://tex.z-dn.net/?f=d%3D148%5C%20m)
radius ![r=74\ m](https://tex.z-dn.net/?f=r%3D74%5C%20m)
Force of gravity
=mg
where m =mass of object
g=acceleration due to gravity on earth
Suppose v is the speed at which spacecraft is rotating so a net centripetal acceleration is acting on spacecraft which is given by
![F_c=\frac{mv^2}{r}](https://tex.z-dn.net/?f=F_c%3D%5Cfrac%7Bmv%5E2%7D%7Br%7D)
![F_c=F_g](https://tex.z-dn.net/?f=F_c%3DF_g)
![\frac{mv^2}{r}=mg](https://tex.z-dn.net/?f=%5Cfrac%7Bmv%5E2%7D%7Br%7D%3Dmg)
![\frac{v^2}{r}=g](https://tex.z-dn.net/?f=%5Cfrac%7Bv%5E2%7D%7Br%7D%3Dg)
![v=\sqrt{gr}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7Bgr%7D)
![v=\sqrt{1450.4}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B1450.4%7D)
Answer:
Mass can never be negative. Everything has mass. Just like how they ask you to find area under the graph in maths. If the area is in the 3rd and 4th quadrant, when calculated, you would get negative answer.However, area can not be negative because it is a place/ location. It's exactly the same as mass.