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4 years ago

When comparing the three atomic models provided, which statement best describes the diagram?

Physics

1 answer:

aliina [53]4 years ago

6 0

C. Three isotopes of the same element because the number of electrons and protons remain the same but the number of neutrons in the nucleus are different. This means that the isotopes have different masses to each other but the same chemical properties.

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If F1 = 390 N and F2 = 550 N , determine the angle θ(0∘≤θ≤180∘) between them, so that the resultant force has a magnitude of FR

Nadya [2.5K]

Answer:

Explanation:

R² = F₁² + F₂² + 2F₁F₂ Cosθ , R is resultant force , θ is angle between them

780² = 390² + 550² + 2 x 390 x 550 Cosθ

608400 = 152100 + 302500 + 429000 Cosθ

Cosθ = .3585

θ = 69 degree.

5 0

3 years ago

The Inner Galactic Plane Survey conducted with the Allen Telescope Array in northern California is an example of a

xz_007 [3.2K]

Given our understanding of Galactic space searches and techniques, we can confirm that the Inner Galactic Plane Survey conducted with the Allen Telescope Array is an example of a targeted search.

A targeted search is when a technique is used not to sweep for general information, but to identify points at which specific processes occur. In the case of the Inner Galactic Plane Survey, the goal is to find points of star formations.

Therefore, we can say that the Inner Galactic Plane Survey conducted with the Allen Telescope Array in northern California is an example of a targeted search.

To learn more visit:

brainly.com/question/6272572?referrer=searchResults

7 0

3 years ago

It takes a crane 59s to lift a flagstone using 342 W of power. How much work is done on the flagstone?

zepelin [54]

Answer: The work done on the flagstone is 20178 J

Explanation:

Power is the rate at which work is done . It is equal to the amount of work done divided by the time it takes to do the work.

$Work=Power\times time$

Given : work = ?

Power = 342 W = 342J/s

Time = 59 s

$Work=342J/s\times 59s=20178J$

Thus the work done on the flagstone is 20178 J

5 0

3 years ago

I need help ASAP please.....

Anna11 [10]

It represents the distance and time, x, Y show that

7 0

3 years ago

A proton of mass 1.67×10-27 kg is being accelerated along a straight line at 7.01×1015 m/s2 in an accelerator. If the proton has

Masja [62]

Answer:

$v_f=7*10^7\frac{m}{s}$

Explanation:

The proton is under a linear motion with constant acceleration. So, we use the kinemtic equations to calculate its final speed. We know its acceleration, its initial speed and its traveled distance. Thus, we use the following equation:

$v_f^2=v_0^2+2ax\\v_f=\sqrt{v_0^2+2ax}\\v_f=\sqrt{(6.63*10^7\frac{m}{s})^2+2(7.01*10^{15}\frac{m}{s^2})(3.63*10^{-2}m)}\\v_f=7*10^7\frac{m}{s}$

5 0

4 years ago