I hope this helps. it was right when i took the test.
Suppose that the distance an aircraft travels along a runway before takeoff is given by Upper D equals (5 divided by 3 )t square
1 answer:
Answer:
a. Time=25seconds
b.distance=1041.67m
Explanation:
a.The equation for in terms of m/s is
after conversion.
To find when speed reaches 300km/hr=83.33m/s, we find and solve for
b. From a, above we already have our t=25seconds as the time it takes before the plane is airborne.
#To find distance travelled in that time , we substitute for in our distance equation:
Hence the distance of the plane before it gets airborne is 1041.67m
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#2
As it is given here
initial speed is
After 4 seconds the final speed is
so here we can use the formula of acceleration using kinematics
so here it will accelerate at 2 m/s^2 rate.
#3
As it is given here
initial it starts from rest
After 2.5 seconds the final speed is
so here we can use the formula of acceleration using kinematics
so here it will accelerate at 6 m/s^2 rate.
#4
i think question is not correct as in first line it is saying about a bag of trash and then in next line it is asking for the position of Jumper and bridge.
Answer:
A) Concentration of A left at equilibrium of we started the reaction with [A] = 2.00 M and [B] = 2.00 M is 0.55 M.
B) Final concentration of D at equilibrium if the initial concentrations are [A] = 1.00 M and [B] = 2.00 M is 0.90 M.
[D] = 0.90 M
Explanation:
With the first assumption that the volume of reacting mixture doesn't change throughout the reaction.
This allows us to use concentration in mol/L interchangeably with number of moles in stoichiometric calculations.
- The first attached image contains the correct question.
- The solution to part A is presented in the second attached image.
- The solution to part B is presented in the third attached image.
