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murzikaleks [220]
3 years ago
7

A generator consists of a rectangular loop with turns of wire spinning at in a uniform magnetic field. The generator output is c

onnected to a series RC circuit consisting of a and a capacitor. What is the average power delivered to the circuit?
Physics
1 answer:
iren [92.7K]3 years ago
5 0
<h3><u>Full question:</u></h3>

A generator consists of a 18-cm by 12-cm rectangular loop with 500 turns of wire spinning at 60 Hz in a 25 mT uniform magnetic field. The generator output is connected to a series RC circuit consisting of a 150 Ω and a 35 μF capacitor.What is the average power delivered to the circuit?

<h3><u>Answer:</u></h3>

The average power delivered to the circiut is 27.5 W

<h3><u>Solution:</u></h3>

Induced emf amplitude = N A B w  

N- Number of turns of the coil

B- Magnetic field

=500 \times(0.18 \times 0.12) \times 0.025 \times(2 \pi 60)

Induced emf amplitude = 101.8 Volt

\begin{aligned}&X_{c}=\frac{1}{(2 p i f C)}=\frac{1}{2 \times \pi \times 60 \times 35 \times 10^{-6}}\\&X_{c}=75.8\ \mathrm{ohm}\end{aligned}

R = 150 ohm

\begin{aligned}&z=\sqrt{\left[R^{2}+X_{c}^{2}\right]}=168 \text { ohm }\\&I_{\text {peak}}=\frac{101.8}{168}=0.606\ \mathrm{A}\\&P_{a v g}=\frac{l^{2} R}{2}=27.5\ \mathrm{W}\end{aligned}

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Explanation:

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Where:

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x0 = initial horizontal position.

v0x = initial horizontal velocity.

t = time.

g = acceleration due to gravity (-9.81 m/s² considering the upward direction as positive).

Please, see the attached figure for a graphical description of the problem. Notice that the origin of the frame of reference is located at the edge of the cliff so that x0 and y0 = 0.

When the rock reaches the ground, the position vector will be (see r1 in the figure):

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Since x0 and y0 = 0:

90 m = v0x · t

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-50 m = 1/2 · g · t²

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90 m = v0x · 3.19 s

v0x = 90 m / 3.19 s

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