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2 years ago

9

What is the electric potential 4.20 m from a -3.37*10^-6 C charge?

2 answers:

pshichka [43]2 years ago

6 0

Answer:

-7221.43

Explanation:

solong [7]2 years ago

5 0

Answer:

$V =-7221.43 \ V$

Explanation:

<u>The Electric Potential</u>

The electric potential at a point is equal to the electric potential energy (measured in joules) of any charged particle at that location divided by the charge (measured in coulombs) of the particle.

To calculate the electric potential of a point charge Q at a distance r, we use the formula:

$\displaystyle V=\frac{kQ}{r}$

Where

$k=9\cdot 10^9\ N.m^2/c^2$

We are given the following data:

$Q=-3.37\cdot 10^{-6}\ c$

r = 4.20 m

Calculating:

$\displaystyle V=\frac{9\cdot 10^9*(-3.37\cdot 10^{-6})}{4.2}$

$\mathbf{V =-7221.43 \ V}$

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While in a car at 4.47 meters per second a passenger drops a ball from a height of 0.70 meters above the top of a bucket how far

viktelen [127]

Answer:

1.7 m

Explanation:

$v_x$ = Velocity of ball in x direction = 4.47 m/s

$u_y$ = Velocity of ball in y direction = 0

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

t = Time taken

$s_y$ = Vertical displacement = 0.7 m

$s_y=u_yt+\dfrac{1}{2}gt^2\\\Rightarrow 0.7=0+\dfrac{1}{2}\times 9.81t^2\\\Rightarrow t=\sqrt{\dfrac{0.7\times 2}{9.81}}\\\Rightarrow t=0.38\ \text{s}$

Horizontal displacement is given by

$s_x=v_xt\\\Rightarrow s_x=4.47\times 0.38\\\Rightarrow s_x=1.7\ \text{m}$

The passenger should throw the ball 1.7 m in front of the bucket.

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2 years ago

If an object absorbs light energy, its thermal energy __________.

german

D), increases. The object absorbs light energy which in turn (energy is energy) usually involves absorbing heat as well.

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2 years ago

What kind of deformation does a cube of Jell-O exhibit when it jiggles?

nadya68 [22]

It depends on chemistry... A physical deformation to the Jell-O.

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3 years ago

What is the period of a simple pendulum 47 cm long (a) on the Earth, and ( b) when it is in a freely falling elevator?

Liula [17]

Answer:

a)1.37 s

b)∞ ( Infinite)

Explanation:

Given that

L= 47 cm ( 1 m =100 cm)

L= 0.47 m

a)

On the earth :

Acceleration due to gravity = g

We know that time period of the simple pendulum given as

$T=2\pi\sqrt{ \dfrac{L}{g_{{eff}}}$

Here

$g_{eff}= g$

Now by putting the values

$T=2\pi \times\sqrt{ \dfrac{0.47}{9.81}}$

T=1.37 s

b)

Free falling elevator :

When elevator is falling freely then

$g_{eff}= 0$ ( This is case of weightless motion)

Therefore

$T=2\pi\sqrt{ \dfrac{L}{0}$

T=∞ (Infinite)

6 0

3 years ago

A 10.0-kg box starts at rest and slides 3.5 m down a ramp inclined at an angle of 10° with the horizontal. If there is no fricti

Alenkinab [10]

Answer:

$v_f = 3.45 m/s$

Explanation:

As we know that box was initially at rest

so here work done by all forces on the box = change in its kinetic energy

so we will have

$mg sin\theta L = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2$

now we have

m = 10 kg

$\theta = 10^0$

L = 3.5 m

so we will have

$10(9.81)sin10 \times 3.5 = \frac{1}{2}(10)(v_f^2 - 0)$

$2(9.81) sin10 \times 3.5 = v_f^2$

so final speed is given as

$v_f = 3.45 m/s$

6 0

2 years ago