Question

What is the electric potential 4.20 m from a -3.37*10^-6 C charge?

Answer 1

Answer:

-7221.43

Explanation:

Answer 2

Answer:

$V =-7221.43 \ V$

Explanation:

The Electric Potential

The electric potential at a point is equal to the electric potential energy (measured in joules) of any charged particle at that location divided by the charge (measured in coulombs) of the particle.

To calculate the electric potential of a point charge Q at a distance r, we use the formula:

$\displaystyle V=\frac{kQ}{r}$

Where

$k=9\cdot 10^9\ N.m^2/c^2$

We are given the following data:

$Q=-3.37\cdot 10^{-6}\ c$

r = 4.20 m

Calculating:

$\displaystyle V=\frac{9\cdot 10^9*(-3.37\cdot 10^{-6})}{4.2}$

$\mathbf{V =-7221.43 \ V}$