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anastassius [24]
3 years ago
12

If you are given a chemical equation and specific amounts for each reactant in grams, how would you determine how much product c

an possibly be made? If you are given a chemical equation and specific amounts for each reactant in grams, how would you determine how much product can possibly be made? 1. Determine which reactant is the limiting reactant. 2. Using conversion factor, convert grams of the limiting reactant to grams of the product. 1. Determine which reactant is the limiting reactant. 2. Convert each reactant into moles of the product. 3. Convert the moles of product, from the limiting reactant, to grams. 1. Convert each reactant into moles of the product. 2. Determine which reactant is the limiting reactant. 3. Convert the moles of product, from the limiting reactant, to grams.
Chemistry
1 answer:
V125BC [204]3 years ago
8 0

Answer:

<em>If you are given a chemical equation and specific amounts for each reactant in grams, you have to follow these steps, in order, to determine how much product can possilby be made:</em>

  • <u><em>1. Convert each reactant into moles of the product. </em></u>
  • <u><em>2. Determine which reactant is the limiting reactant. </em></u>
  • <u><em>3. Convert the moles of product, from the limiting reactant, to grams</em></u><u>.</u>

Justification:

The balanced chemical equation, through the coefficients, represents the proportions, in terms of mole ratios, in that each reactant chemically react with each other to form each product.

So, if you are given specific aomunts for each reactant in grams, you must start by converting each reactant amount into mole numbers, using the molar mass of each one.

Then, using the theoretical mole ratios (from the coefficients of the balanced chemical equation) you can determine how much of each product can be produced, in terms of moles, first starting with the complete consumption of one of the reactants, and then doing the same with each of the other reactants, one by one.

The reactant that yields the least amount of product is the limiting reactant, since it will be consumed completely once that amount of product is obtainded, while the other reactants will be in excess.

Now, that you have the number of moles that can be produced from the limiting reactant, you can convert it into grams of product, just using the molar mass of the same.

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Calculate the number of atoms in 112 g of iron.​
mr_godi [17]

Answer:

1 mole of iron (Fe) = 56 g (molar mass)

Since 56 g of iron = 1 mol.

Therefore, 112 g of iron= 1/ 56 ×112 mol = 2 mol.

Explanation:

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The reaction for photosynthesis producing glucose sugar and oxygen gas is:
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<u><em>1.5 grams of glucose is produced from 2.20 g of CO₂.</em></u>

To find the mass of glucose produced, first you must know the balanced reaction. For this, the Law of Conservation of Matter is followed.

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

So, in this case, the balanced reaction is:

6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the amounts of moles of each reactant and product participate in the reaction:

  • CO₂: 6 moles
  • H₂O: 6 moles
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So, you know that 2.20 g of CO₂ react, whose molar weight is 44.01 g/mole. By definition of molar mass, 1 mole of CO₂ has 44.01 g. So, the number of moles that 2.20 grams of the compound represent is calculated as:

moles of CO_{2} =2.20 grams*\frac{1 mole}{44.01 grams}

moles of CO₂= 0.05 moles

Now you must follow the following rule of three: if by stoichiometry of the reaction 6 moles of CO₂ produce 1 mole of C₆H₁₂O₆, 0.05 moles of CO₂ produce how many moles of C₆H₁₂O₆?

moles of C_{6} H_{12} O_{6} =\frac{0.05moles of CO_{2} *1 mole of C_{6} H_{12} O_{6}}{6moles of CO_{2}}

moles of C₆H₁₂O₆= 8.33*10⁻³

Being the molar mass of glucose 180.18 g/mole, the mass that 8.33*10⁻³ moles of the compound represent is calculated as:

mass of glucose =8.33*10^{-3} moles*\frac{180.18 grams}{1 mole}

<em>mass of glucose= 1.5 grams</em>

Then, <u><em>1.5 grams of glucose is produced from 2.20 g of CO₂.</em></u>

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A solution is made by adding 35.5 mL of concentrated hydrochloric acid ( 37.3 wt% , density 1.19 g/mL1.19 g/mL ) to some water i
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Answer:

1.73 M

Explanation:

We must first obtain the concentration of the concentrated acid from the formula;

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Where

Co= concentration of concentrated acid = (the unknown)

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d= density of concentrated acid = 1.19 g/ml

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We can now use the dilution formula

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Co= concentration of concentrated acid= 12.16 M

Vo= volume of concentrated acid = 35.5 ml

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Vd= volume of dilute acid = 250ml

Substituting values and making Cd the subject of the formula;

Cd= CoVo/Vd

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