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anastassius [24]
3 years ago
12

If you are given a chemical equation and specific amounts for each reactant in grams, how would you determine how much product c

an possibly be made? If you are given a chemical equation and specific amounts for each reactant in grams, how would you determine how much product can possibly be made? 1. Determine which reactant is the limiting reactant. 2. Using conversion factor, convert grams of the limiting reactant to grams of the product. 1. Determine which reactant is the limiting reactant. 2. Convert each reactant into moles of the product. 3. Convert the moles of product, from the limiting reactant, to grams. 1. Convert each reactant into moles of the product. 2. Determine which reactant is the limiting reactant. 3. Convert the moles of product, from the limiting reactant, to grams.
Chemistry
1 answer:
V125BC [204]3 years ago
8 0

Answer:

<em>If you are given a chemical equation and specific amounts for each reactant in grams, you have to follow these steps, in order, to determine how much product can possilby be made:</em>

  • <u><em>1. Convert each reactant into moles of the product. </em></u>
  • <u><em>2. Determine which reactant is the limiting reactant. </em></u>
  • <u><em>3. Convert the moles of product, from the limiting reactant, to grams</em></u><u>.</u>

Justification:

The balanced chemical equation, through the coefficients, represents the proportions, in terms of mole ratios, in that each reactant chemically react with each other to form each product.

So, if you are given specific aomunts for each reactant in grams, you must start by converting each reactant amount into mole numbers, using the molar mass of each one.

Then, using the theoretical mole ratios (from the coefficients of the balanced chemical equation) you can determine how much of each product can be produced, in terms of moles, first starting with the complete consumption of one of the reactants, and then doing the same with each of the other reactants, one by one.

The reactant that yields the least amount of product is the limiting reactant, since it will be consumed completely once that amount of product is obtainded, while the other reactants will be in excess.

Now, that you have the number of moles that can be produced from the limiting reactant, you can convert it into grams of product, just using the molar mass of the same.

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Calculate the EMF of the following cell at standard conditions (temperature = 25o C, pressure = 1 atmosphere): Ni | Ni2+ | | Cu2
kakasveta [241]

Answer:

a) +0.574 V

b) +0.573V

Explanation:

The EMF is the electromotive force, which is the property of a device that intends to generate electrical current. The EMF of a cell can be calculated by the Nernst equation:

Emf = E° - (0.0592/n)*logQ

Where E° is the standard reduction potential of the cell, n is the number of electrons involved in the reaction, and Q is the reaction quotient ([products]/[reactants]).

In the cell, a redox reaction happens. One substance oxides (lose electrons and become a cation), and the other one reduces (gains electrons and becomes an anion). Each reaction has a reduction potential (E), which indicates how easily is to the reduction happens (as higher E as easy).

For the overall reaction, E° = Ereduction - Eoxidation. To the cell given, Ni is oxidizing, and Cu⁺² is reducing, so, the half-reactions with its E (which can be found at tables), and the overall reaction are:

Ni(s) → Ni⁺² + 2e⁻ E = -0.24 V

Cu⁺² + 2e⁻ → Cu(s) E = +0.337 V

Ni(s) + Cu⁺² → Ni⁺² + Cu(s)

E° = +0.337 - (-0.24)

E° = +0.577 V

As we can see, there're 2 electrons involved in the reaction, so n =2.

The solids don't take place in the Q value, so:

Q = [Ni⁺²]/[Cu⁺²]

a) Q = 0.1/0.08 = 1.25

Emf = 0.577 - (0.0592/2)*log(1.25)

Emf = 0.577 - 0.003

Emf = +0.574 V

b) Q = 0.4/0.3 = 1.33

Emf = 0.577 - (0.0592/2)*log(1.33)

Emf = 0.577 - 0.004

Emf = +0.573 V

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