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ser-zykov [4K]
3 years ago
6

Consider a disubstituted aromatic compound. The parent name is benzene and there is a chloro and bromo substituent. Disubstitute

d benzenes can be described using the terms ortho, meta and para, depending on their relative distance from each other. The terms are often just abbreviated as o, m and p. In addition, the IUPAC name can use locant numbers instead of the descriptor. Br
Select the correct names for the structure.
1. 1-bromo-3-chlorobenzene
2. 3-bromo-1-chlorobenzene
3. meta-bromochlorobenzene
4. o-bromochlorobenzene
5. ortho-bromochlorobenzene
6. m-bromochlorobenzene
Chemistry
1 answer:
Marina86 [1]3 years ago
8 0

Answer:The correct names for the structure are:

--> 1. 1-bromo-3-chlorobenzene.

--> 3. meta-bromochlorobenzene.

--> 6. m-bromochlorobenzene.

Explanation:

Benzene is the simplest member of the aromatic hydrocarbons. It has a ring structure consisting of six carbon and six hydrogen atoms. This equally means that a benzene can have up to six substituents. One of the chemical properties is that benzene and other members of its series undergo substitution reaction whereby one or more of its six hydrogen atoms is replaced by monoatomic reagents.

Disubstituted benzene consists of two substituents which are described based on either numerical locants or specific words for the three possible forms.

The numerical locant method are used the same naming substitutes of other hydrocarbons. From the question, the numerical locant method was derived through using the following steps:

--> the functional group is benzene

--> there are two substituents which includes bromine( written as bromo) and chlorine ( written as chloro)

--> while placing the number, it's done alphabetically ('1-bromo' comes before '3-chloro') in a clockwise manner. This is to give chorine the lowest locant number.

The second naming method for a disubstituted benzene is the the ortho-, meta-, para- (or their singel letter equivalent) nomenclature method. This is only used for benzene structures.

--> ortho or O : this is used when the substituents are close to each other in the benzene ring.

--> meta or (m) : This is used when the substituents are separated by one carbon in the benzene ring.

--> para or (p): This is used when the substituents are across each other in the benzene ring

From the question, the bromine substituent is separated from the chlorine by one carbon atom, therefore it's meta-bromochlorobenzene or m-bromochlorobenzene.

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Answer:

How does methane gas affect the environment?

If methane leaks into the air before being used — from a leaky pipe, for instance — it absorbs the sun's heat, warming the atmosphere. For this reason, it's considered a greenhouse gas, like carbon dioxide.

Explanation:

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3 years ago
Write and balance the chemical equation for the reaction associated with ΔHof of Li3N(s). What is the sum of all of the coeffici
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Explanation:

In this reaction, the reactants are Li and N2. The product is Li3N

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5 0
3 years ago
Calculate the molality of a solution that contains 51.2 g of naphthalene, C10H8, in 500 mL of carbon tetrachloride. The density
PtichkaEL [24]

<u>Answer:</u> The molality of naphthalene solution is 0.499 m

<u>Explanation:</u>

Density is defined as the ratio of mass and volume of a substance.

\text{Density}=\frac{\text{Mass}}{\text{Volume}} ......(1)

Given values:

Volume of carbon tetrachloride = 500 mL

Density of carbon tetrachloride = 1.60 g/mL

Putting values in equation 1, we get:

\text{Mass of carbon tetrachloride}=(1.60g/mL\times 500mL)=800g

Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg. The formula used to calculate molarity:

\text{Molality of solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent (in g)}} .....(2)

Given values:

Given mass of naphthalene = 51.2 g

Molar mass of naphthalene = 128.17 g/mol

Mass of solvent = 800 g

Putting values in equation 2, we get:

\text{Molality of naphthalene}=\frac{51.2\times 1000}{128.17\times 800}\\\\\text{Molality of naphthalene}=0.499m

Hence, the molality of naphthalene solution is 0.499 m

4 0
2 years ago
In general, which attractions are stronger: intermolecular or intramolecular? Research and explain a quantitative comparison bet
murzikaleks [220]

Answer is: intramolecular attractions are stronger.

Intramolecular attractions are the forces between atoms in molecule.

There are several types of intramolecular forces: covalent bonds, ionic bonds.

Intermolecular forces are the forces between molecules. The stronger are intermolecular forces, the higher is boiling point of compound, because more energy is needed to break interaction between molecules.

There are several types of intermolecular forces: hydrogen bonding, ion-induced dipole forces, ion-dipole forces andvan der Waals forces.

Hydrogen bonds are approximately 5% of the bond strength of covalent C-C or C-H bonds.

Hydrogen bonds strength in water is approximately 20 kJ/mol, strenght of carbon-carbon bond is approximately 350 kJ/mol and strengh of carbon-hydrogen bond is approximately 340 kJ/mol.

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8 0
3 years ago
For the second-order reaction below, the rate constant of the reaction is 9.4 x 10^-3 M^-1 s^-1. How long (in sec) is required t
Archy [21]

Answer : The time taken by the reaction is 2.2\times 10^2s

Explanation :

The expression used for second order kinetics is:

kt=\frac{1}{[A_t]}-\frac{1}{[A_o]}

where,

k = rate constant = 9.4\times 10^{-3}M^{-1}s^{-1}

t = time = ?

[A_t] = final concentration = 0.40 M

[A_o] = initial concentration = 2.16 M

Now put all the given values in the above expression, we get:

(9.4\times 10^{-3})\times t=\frac{1}{0.40}-\frac{1}{2.16}

t=216.706s\aprrox 2.2\times 10^2s

Therefore, the time taken by the reaction is 2.2\times 10^2s

7 0
4 years ago
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