All categories

3 years ago

An insect sit's on the edge of a spinning record that has

Physics

1 answer:

attashe74 [19]3 years ago

5 0

Answer:

1.67rad/s^2

Explanation:

a= v^2/r

a = 0.5^2/0.15

a= 1.67 rad/s^2

You might be interested in

The knee extensors insert on the tibia at an angle of 30 degrees (from the longitudinal axis of the tibia), at a distance of 3 c

Reika [66]

Answer:

the knee extensors must exert 15.87 N

Explanation:

Given the data in the question;

mass m = 4.5 kg

radius of gyration k = 23 cm = 0.23 m

angle ∅ = 30°

∝ = 1 rad/s²

distance of 3 cm from the axis of rotation at the knee r = 3 cm = 0.03 m

using the expression;

ζ = I∝

ζ = mk²∝

we substitute

ζ = 4.5 × (0.23)² × 1

ζ = 0.23805 N-m

from; ζ = rFsin∅

F = ζ / rsin∅

we substitute

F = 0.23805 / (0.03 × sin( 30 ° )

F = 0.23805 / (0.03 × 0.5)

F F = 0.23805 / 0.015

F = 15.87 N

Therefore, the knee extensors must exert 15.87 N

7 0

3 years ago

Scientific inquiry includes many different activities. Which of the following is a process that is typically performed during a

Juli2301 [7.4K]

D. All of these, they’re all part of scientific inquiry

7 0

3 years ago

Read 2 more answers

) A steel guitar string with a diameter of 1.00 mm is stretched between supports 80.0 cm apart. The temperature is 0.0°C. (a) Fi

ladessa [460]

Answer: a. Mass per unit length =0.0245kg/m

b. Tension =2.45x10^-8N

C. Tension = 2.45 x10^-8N

Fundamental frequency =200Hz

Explanation:

7 0

4 years ago

Which statement describes the molecules and a reaction once it reaches equilibrium

shepuryov [24]

Answer:

A: They maintain stable concentrations.

Explanation:

Hopefully this helps!

4 0

3 years ago

Water is flowing in a fire hose with a velocity of 1.0 m/s and a pressure of 200000 Pa. At the nozzle the pressure decreases to

jeka57 [31]

Answer:

The velocity is $v_n =14.09 \ m/s$

Explanation:

From the question we are told that

The velocity of the water in the pipe is $v_i = 1.0 \ m/s$

The pressure inside the pipe is $P_i = 200000 \ Pa$

The pressure at the nozzle is $P_n = 101300 \ Pa$

The density of water is $\rho = 1000 \ kg / m^3$

For the height $h_1 = h_2 = h$

where $h_1$ is height of water in the pipe

and $h_2$ is height of water at the nozzle

Generally Bernoulli equation is represented as

$\frac{1}{2} \rho * v_i ^2 + \rho * g * h_1 + P_i = \frac{1}{2} \rho v_n ^2 + \rho * g* h_2 + P_n$

=> $\frac{1}{2} \rho * v_i ^2 + \rho * g * h + P_1 = \frac{1}{2} \rho v_n ^2 + \rho * g* h + P_2$

Where $v_n$ is the velocity of the water at the nozzle

Now making $v_n$ the subject

$v_n = \sqrt{\frac{2}{\rho} [ P_i - Pn + \frac{1}{2} \rho v_i^2}$

substituting values

$v_n = \sqrt{\frac{2}{1000} [ 200000 - 101300 + \frac{1}{2} (1000 * (1.0)^2)}$

$v_n =14.09 \ m/s$

6 0

4 years ago