Answer:
Explanation:
Given that,
A block of mass m = 0.2kg
Amplitude of oscillation A = 0.3m
Spring Constant k = 12N/m
We want to rank the period of oscillation in each case from the smallest to the largest.
Period of oscillation can be determine using
T = 2π√m/k
Where,
T is period in seconds
m is mass in kg
k is spring constant in N/m
So, the only things that affect the period is mass and the spring constant
A. Using the above information
Where m = 0.2kg and k = 12 N/m
Then, T = 2π√m/k
T = 2π√(0.2/12)
T = 2π × 0.129
Ta = 0.81 seconds
B. The amplitude is change to 1.6m, A = 1.6m
The period T for a pendulum is nearly independent of amplitude.
Since the period is independent of the amplitude, then, the period does not change
So, Tb = Ta = 0.81seconds
C. If the mass is change to 1.6kg
Now, m=1.6kg
Then, T = 2π√m/k
T = 2π√(1.6/12)
T = 2π × 0.365
Tc = 2.28 seconds
D. If the force constant is change to 30N/m
Now, k = 30
Then, T = 2π√m/k
T = 2π√(0.2/ 30)
T = 2π × 0.0816
Td = 0.513 seconds
E. The small resistive force does not affect the period
So the period remains unchanged
Ta = Te = 0.81 seconds
Ranking the periods
Tc > Ta = Tb = Te > Td
