Answer:
5.5 N at 50.8° north of west.
Explanation:
To find the resultant of these forces, we have to resolve each force along the x- and y-direction, then find the components of the resultant force, and then calculate the resultant force.
The three forces are:
 (east)
 (east)
 (west)
 (west)
 (at 60° north of west)
 (at 60° north of west)
Taking east as positive x-direction and north as positive y-direction, the components of the forces along the 2 directions are:



Threfore, the components of the resultant force are:

Therefore, the magnitude of the resultant force is

And the direction is:

And since the x-component is negative, it means that this angle is measured as north of west.
 
        
             
        
        
        
Answer:
The time taken is 84 seconds, please give the brainliest award would be much appreciated.
 
        
             
        
        
        
Answer:
1.2826 x 10^-13 m 
Explanation:

Here, k be the kinetic energy and m be the mass
K = 50 KeV = 50 x 1.6 x 10^-16 J = 80 x 10^-16 J
m = 1.67 x 10^-27 kg 

λ = 1.2826 x 10^-13 m 
 
        
             
        
        
        
Answer:
The take-off speed is 41.48 
Explanation:
Given : 
Range  m
 m
Projectile angle  13°
 13°
From the formula of range,
   
Find the velocity from above equation,
   
    ( ∵
                              ( ∵  
  )
 )
    
 
Therefore, the take-off speed is 41.48 