5x - 2x + 8 = 2 + 6x + 6
Add like terms:
5x - 2x = 3x
2 + 6 = 8
3x + 8 = 6x + 8
To isolate the variable, subtract 6x from both sides of the equation:
3x - 6x = -3x
-3x + 8 = 8
Now subtract 8 from both sides:
8 - 8 = 0
-3x = 0
To finish, divide both sides by -3:
0 ÷ -3x = 0
The answer is x = 0
Hope this helps.
Answer:
The depreciation each year is option B. $1500.00
Step-by-step explanation:
Initial value of car = $9600
Salvage value = $600
Salvage value is the final value of product after all the depreciation have been applied on the product.
So, total depreciation on the car = 
Also, it is given that the depreciation occurs at a straight line method i.e. same depreciation occurs every year.
Depreciation in 6 years = $9000
Depreciation in 1 year =

Hence, option B. $1500 is the correct answer for the depreciation every year.