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Aloiza [94]
4 years ago
15

If this wave has frequency of 15 hz. what is the wavelength of that wave ?

Physics
1 answer:
Aneli [31]4 years ago
4 0
Do you have any other information? Like the velocity of the wave?
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If you were asked how to evaluate scientific evidence, what would you would want to include in your answer?
raketka [301]
You would want to include qualitative and quantitative evidence
6 0
4 years ago
A 2550 pound roller coaster starts from rest and is launched such that it crests a 119 ft high hill with a speed of 57 mph. The
Feliz [49]

To solve this problem we will apply the concepts related to energy conservation. For this purpose we will have that all the changes occurred in the energy change will be equivalent to the change in the potential and kinematic energies of the body. At the same time we will consider that the change in the final energy of the system will be reflected in the work of the system, therefore,

\Delta E = KE+PE

E_i - Fd = \frac{1}{2}mv^2+Wh

Here,

F = Force

m = mass

v = Velocity

h = Height

d = Distance

W = mg \rightarrow \text{Weight/Force Weight}

E_i =\frac{1}{2}mv^2+Wh+Fd

E_i = \frac{1}{2} (\frac{W}{g})v^2 +Wh+fd

Replacing we have,

E_i = \frac{1}{2} (\frac{2550pounds}{32.2ft/s^2})(57mi/h(\frac{1.467ft/s}{1mi/h}))+(2550pounds)(119ft)+(100pounds)(583ft)

E_i =365061ft\cdot lb

Therefore the launch energy is 365061ft-lb

3 0
4 years ago
If 51.9 C of charge are transferred in a specific lightning strike and the potential difference is ∆V = 10.93 MV, how much energ
MA_775_DIABLO [31]

Quantity of charge unloaded = 51.9 Coulombs

Potential difference = 10.93 megavolts = 1.093 x 10⁷ volts

1 volt = 1 joule per coulomb

1.093 x 10⁷ volts = 1.093 x 10⁷ joules per coulomb

Energy = (1.093 x 10⁷ J/C) x (51.9 C)

Energy = 567.267 megaJoules

That's <em>5.67 x 10⁸ Joules</em> .

==> My wife's blow-dryer is marked 1260 watts.

If the energy in this lightning strike could be collected, bottled, stored, and used as needed, it could run my wife's blow-dryer for 125 hours.  That would save us more than $30 on our electric bill !

8 0
3 years ago
If you wanted to know how much the temperature of a particular piece of material would rise when a known amount of heat was adde
mars1129 [50]

Answer:

Option (b) is correct.

Explanation:

The amount of heat required to raise the temperature of substance of mass 1 kg by 1 degree C, is called specific heat of the substance.

The formula of the specific heat is

H = m c (T' - T)

where, m is the mass, c is the specific heat and T' - T is the change in temperature.

So, to know the rise in temperature, by adding the known amount of heat, the specific heat is required.

So, option (b) is correct.

4 0
3 years ago
If you weigh 690 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun an
Dennis_Churaev [7]

Answer:

W' = 1.66 x 10¹⁴ N

Explanation:

First, we will calculate the mass:

W = mg

where,

W = weight on earth = 690 N

m = mass = ?

g = acceleration due to gravity on earth = 9.8 m/s²

Therefore,

m = \frac{W}{g} = \frac{690\ N}{9.8\ m/s^2}\\\\m = 70.4\ kg

Now, we will calculate the value of g on the neutron star:

g' = \frac{GM}{R^2}

where,

g' = acceleration due to gravity on the surface of the neutron star = ?

G = Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

M = Mass of the Neutron Star = 1.99 x 10³⁰ kg

R = Radius of the Neutron Star = 15 km/2 = 7.5 km = 7500 m

Therefore,

g' = \frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(1.99\ x\ 10^{30}\ kg)}{(7500\ m)^2}\\\\g' = 2.36\ x\ 10^{12}\ m/s^2

Therefore, the weight on the surface of the neutron star will be:

W' = mg'\\W' = (70.4\ kg)(2.36\ x\ 10^{12}\ m/s^2)

<u>W' = 1.66 x 10¹⁴ N</u>

7 0
3 years ago
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