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NeTakaya
3 years ago
7

A 425.00-gram sample of a compound decomposes into 196.01 grams of carbon, 41.14 grams of hydrogen, 130.56 grams of oxygen, and

57.29 grams of silicon. Experiments have shown the compound has a molecular weight of 208.329. What is the molecular formula?
Chemistry
1 answer:
valentinak56 [21]3 years ago
3 0

Answer:

C₈H₂₀O₄Si

Explanation:

The moles of each atom (Using atomic weight) are:

C: 196.01g × (1mol / 12.01g) = 16.32 moles of C

H: 41.14g × (1mol / 1.01g) = 40.73 moles of H

O: 130.56g × (1mol / 16g) = <em>8.16</em> moles of O

Si: 57.29g × (1mol / 28.09g) = <em>2.04</em> moles of Si

Dividing in the number of moles of Si to obtain the simplest ratio:

C: 16.32mol C / 2.04mol: 8

H: 40.73mol H / 2.04mol: 20

O: 8.16 mol O / 2.04mol: 4

Si: 2.04mol / 2.04mol: 1

Thus, empirical formula of the compound is:

<em>C₈H₂₀O₄Si</em>.

Molar mass for this formula is:

12.01g/mol × 8 + 1.01g/mol × 20 + 16g/mol × 4 + 28.09g/mol × 1 =

208.37 g/mol ≈ Molecular weight obtained in the experiment.

Thus, molecular formula of the compound is:

<em>C₈H₂₀O₄Si</em>

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2Al2O3 (s) + 3C (s) LaTeX: \longrightarrow ⟶ 4Al (s) + 3CO2 (g)
densk [106]

Answer:

Percent yield = 79.79 %

Explanation:

Given data:

Mass of Al₂O₃ = 821 g

Mass of Al = 349 g

Percent yield = ?

Solution:

Chemical equation:

2Al₂O₃ + 3C     →      4Al  + 3CO₂

Number of moles of Al₂O₃:

Number of moles = mass/molar mass

Number of moles = 821 g/ 101.96 g/mol

Number of moles = 8.1 mol

Now we will compare the moles of Al with Al₂O₃.

                Al₂O₃        :         Al

                    2           :          4

                  8.1           :      4/2×8.1 = 16.2 mol

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Mass = number of moles × molar mass

Mass = 16.2 mol ×  27 g/mol

Mass = 437.4 g

Percent yield:

Percent yield = (actual yield / theoretical yield)× 100

Percent yield =  (349 g/ 437.4 g) × 100

Percent yield = 79.79 %

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