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Alexandra [31]
3 years ago
7

Which of the following might constitute an act of plagiarism?

Chemistry
2 answers:
Dafna1 [17]3 years ago
7 0
Plagiarism can be seen in different ways, but the most common is blatantly stealing someone else’s work and claiming it as your own.

If someone steals, let’s say a renowned psychologists’ work and claims it as their own homework, that’s plagiarism.

Hope this helps!
Elina [12.6K]3 years ago
4 0
Taking credit for a someone else's research or written work
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Match each substance with the correct designation for the equation HSO3- + CH3NH2 <=> SO32- + CH3NH3+ HSO3- CH3NH2 SO32- C
Zanzabum

Answer:

HSO_3^-: conjugate acid of SO_3^{2-}

CH_3NH_2 : conjugate base of CH_3NH_3^+

SO_3^{2-} : conjugate base of HSO_3^-

CH_3NH_3^+ : conjugate acid of CH_3NH_2

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

HSO_3^-+CH_3NH_2\rightleftharpoons SO_3^{2-}+CH_3NH_3^+

Here in forward reaction CH_3NH_2 is accepting a proton, thus it is considered as a base and after accepting a proton, it forms CH_3NH_3^+ which is a conjugate acid.

And HSO_3^-  is losing a proton, thus it is considered as an acid and after loosing a proton, it forms SO_3^{2-} which is a conjugate base.

Similarly in the backward reaction, CH_3NH_3^+ is loosing a proton, thus it is considered as a acid and after loosing a proton, it forms CH_3NH_2 which is a conjugate base.

And SO_3^{2-}  is accepting a proton, thus it is considered as a base and after accepting a proton, it forms HSO_3^{-} which is a conjugate acid.

4 0
3 years ago
What do you think is meant by the phrase "a balanced diet"?
Maurinko [17]
To have the right combinations of foods to provide nutrients
5 0
3 years ago
If 10.g of AgNo3 is available, what volume of 0.25 M AgNo3 can be prepared
Marianna [84]
The equation is L = m/M
First, covert 10. grams of AgNO3 to moles which is 0.059 moles.
Divide 0.059 moles by 0.25M which is 0.24 liters.
3 0
3 years ago
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