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Alexandra [31]
3 years ago
7

Which of the following might constitute an act of plagiarism?

Chemistry
2 answers:
Dafna1 [17]3 years ago
7 0
Plagiarism can be seen in different ways, but the most common is blatantly stealing someone else’s work and claiming it as your own.

If someone steals, let’s say a renowned psychologists’ work and claims it as their own homework, that’s plagiarism.

Hope this helps!
Elina [12.6K]3 years ago
4 0
Taking credit for a someone else's research or written work
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Answer:

okay but give me brainliest

Explanation:

A volcano is formed when hot molten rock, ash and gases escape from an opening in the Earth's surface. The molten rock and ash solidify as they cool, forming the distinctive volcano shape shown here. As a volcano erupts, it spills lava that flows downslope. Volcanic flows are called lahars.

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Rounded to the nearest whole number, how many neutrons, on average, are in an atom of osmium? 76 114 190 266
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Identify the acids and the bases in the chemical equation ​
agasfer [191]
<h3><u>Answer;</u></h3>

Acids;  HCl and HC5H5N+

Bases; C5H5N and Cl-

<h3><u>Explanation;</u></h3>
  • According to Bronsted-Lowry Theory an acid is a proton or hydrogen ion donor while a base is a proton or a hydrogen ion acceptor.
  • In this case,<u> both HCl and HC5H5N+ are acids</u> as <u>they are donors of hydrogen ions</u>. HCl is an acid to the forward reaction while HC5H5N+ is a acid to the reverse reaction.
  • On the other hand, <u>C5H5N and Cl- are bases</u>, <u>they are acceptors of hydrogen  ions</u>. Cl-  is a base in the reverse reaction while C5H5N is a base in the forward reaction.
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From increasing atomic mass. He also made groups and periods.
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A 50.0-g sample of liquid water at 25.0 °c is mixed with 23.0 g of water at 79.0 °c. the final temperature of the water is ___
I am Lyosha [343]

<span><span>m1</span>Δ<span>T1</span>+<span>m2</span>Δ<span>T2</span>=0</span>

<span><span>m1</span><span>(<span>Tf</span>l–l<span>T<span>∘1</span></span>)</span>+<span>m2</span><span>(<span>Tf</span>l–l<span>T<span>∘2</span></span>)</span>=0</span>

<span>50.0g×<span>(<span>Tf</span>l–l25.0 °C)</span>+23.0g×<span>(<span>Tf</span>l–l57.0 °C)</span>=0</span>

<span>50.0<span>Tf</span>−1250 °C+23.0<span>Tf</span> – 1311 °C=0</span>

<span>73.0<span>Tf</span>=2561 °C</span>

<span><span>Tf</span>=<span>2561 °C73.0</span>=<span>35.1 °C</span></span>

8 0
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