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3 years ago

Rachel carson wrote this book, which exposed the deadly impact of ddt and chemical pesticides on wildlife.

Chemistry

1 answer:

mixer [17]3 years ago

5 0

She wrote "Silent Spring", which is an intriguing read.

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Johanna and Paige are visiting their grandparents in Fort Lauderdale in June. The girls think that it is

sukhopar [10]

C is your answer common sense

7 0

2 years ago

Read 2 more answers

Sodium electron configuration

Alex73 [517]

Full:

1s² 2s² 2p⁶ 3s¹

Abbreviated:

[Ne] 3s¹

4 0

3 years ago

What elements start with Ne

tatyana61 [14]

The element that starts with Ne is Neon.

3 0

3 years ago

At elevated temperatures, molecular hydrogen and molecular bromine react to partially form hydrogen bromide:

gayaneshka [121]

Answer: The moles of bromine gas at equilibrium is 0.324 moles.

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ .......(1)

Calculating the initial moles of hydrogen and bromine gas:

For hydrogen gas:

Moles of hydrogen gas = 0.682 mol

Volume of solution = 2.00 L

Putting values in equation 1, we get:

$\text{Molarity of solution}=\frac{0.682mol}{2.00L}=0.341M$

For bromine gas:

Moles of bromine gas = 0.440 mol

Volume of solution = 2.00 L

Putting values in equation 1, we get:

$\text{Molarity of solution}=\frac{0.440mol}{2.00L}=0.220M$

Now, calculating the molarity of hydrogen gas at equilibrium by using equation 1:

Equilibrium moles of hydrogen gas = 0.566 mol

Volume of solution = 2.00 L

Putting values in equation 1, we get:

$\text{Molarity of solution}=\frac{0.566mol}{2.00L}=0.283M$

Change in concentration of hydrogen gas = 0.341 - 0.283 = 0.058 M

This change will be same for bromine gas.

Equilibrium concentration of bromine gas = $(\text{Initial concentration}-\text{Change in concentration})=0.220-0.058=0.162M$

Now, calculating the moles of bromine gas at equilibrium by using equation 1:

Molarity of bromine gas = 0.162 M

Volume of solution = 2.00 L

Putting values in equation 1, we get:

$0.162M=\frac{\text{Moles of bromine gas}}{2.00L}\\\\\text{Moles of bromine gas}=(0.162mol/L\times 2.00L)=0.324mol$

Hence, the moles of bromine gas at equilibrium is 0.324 moles.

5 0

3 years ago

Zn + 2HCl → ZnCl2 + H2 What is the half reaction for the reduction of hydrogen in the reaction?

timama [110]

Answer:

2H^+ +2e -> h2(g)

Explanation:

Since hydrogen is reduced, look for a decrease in oxidation number and the gain of electrons.

8 0

3 years ago