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3 years ago

How to graph this equation

Mathematics

1 answer:

VLD [36.1K]3 years ago

7 0

Graph the trigonometric function using the amplitude,period,phase shift and vertical shift.
Vertical Asymptotes:x=pi/6 =pi n/2 where n is an integer
Amplitude is none
period is pi/2
phase shift is pi/6 to the right
vertical shift is 0

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A bottle filled with juice weighs 8 pounds. One morning, George drank 2/3 of the juice in the filled bottle. The bottle and the

Marysya12 [62]

The remaining weight of the empty bottle is 0.5 because each third of the bottle weighs 2.5 pounds and of the remaining juice and the bottle was 3 pounds 2.5 subtracted from 3 is 0.5

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3 years ago

Nicole has a machine that will produce a number from through when she pushes a button. If she pushes the button, what is:

Lina20 [59]

Answer: 9/50 There is going to be 18% that the number which will be produced after Nicole will push the button will be ae one digit number

Step-by-step explanation:

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3 years ago

Jerry needs 216 posts to build a fence. He has 88 posts and needs P more. Write an equation that you could use to find the numbe

devlian [24]

Answer:

P = 128 Post

Step-by-step explanation:

Total post needed = 216 posts

Number of post Jerry has = 88 posts

Number of posts jerry still needs = P

Total = Number of post Jerry has + Number of posts jerry still needs

216 = 88 + P

216 - 88 = P

128 = P

P = 128 Post

7 0

3 years ago

The sum of first three terms of a finite geometric series is -7/10 and their product is -1/125. [Hint: Use a/r, a, and ar to rep

Alchen [17]

Ooh, fun

geometric sequences can be represented as
$a_n=a(r)^{n-1}$
so the first 3 terms are
$a_1=a$
$a_2=a(r)$
$a_2=a(r)^2$

the sum is -7/10
$\frac{-7}{10}=a+ar+ar^2$
and their product is -1/125
$\frac{-1}{125}=(a)(ar)(ar^2)=a^3r^3=(ar)^3$

from the 2nd equation we can take the cube root of both sides to get
$\frac{-1}{5}=ar$
note that a=ar/r and ar²=(ar)r
so now rewrite 1st equation as
$\frac{-7}{10}=\frac{ar}{r}+ar+(ar)r$
subsituting -1/5 for ar
$\frac{-7}{10}=\frac{\frac{-1}{5}}{r}+\frac{-1}{5}+(\frac{-1}{5})r$
which simplifies to
$\frac{-7}{10}=\frac{-1}{5r}+\frac{-1}{5}+\frac{-r}{5}$
multiply both sides by 10r
-7r=-2-2r-2r²
add (2r²+2r+2) to both sides
2r²-5r+2=0
solve using quadratic formula
for $ax^2+bx+c=0$
$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$
so
for 2r²-5r+2=0
a=2
b=-5
c=2

$r=\frac{-(-5) \pm \sqrt{(-5)^2-4(2)(2)}}{2(2)}$
$r=\frac{5 \pm \sqrt{25-16}}{4}$
$r=\frac{5 \pm \sqrt{9}}{4}$
$r=\frac{5 \pm 3}{4}$
so
$r=\frac{5+3}{4}=\frac{8}{4}=2$ or $r=\frac{5-3}{4}=\frac{2}{4}=\frac{1}{2}$

use them to solve for the value of a
$\frac{-1}{5}=ar$
$\frac{-1}{5r}=a$
try for r=2 and 1/2
$a=\frac{-1}{10}$ or $a=\frac{-2}{5}$

test each
for a=-1/10 and r=2
a+ar+ar²= $\frac{-1}{10}+\frac{-2}{10}+\frac{-4}{10}=\frac{-7}{10}$
it works

for a=-2/5 and r=1/2
a+ar+ar²= $\frac{-2}{5}+\frac{-1}{5}+\frac{-1}{10}=\frac{-7}{10}$
it works

both have the same terms but one is simplified

the 3 numbers are $\frac{-2}{5}$ , $\frac{-1}{5}$ , and $\frac{-1}{10}$

6 0

3 years ago

two glasses of milk and 3 snack bars have a total of 78 carbohydrates (carbs), and 4 glasses of milk and 3 snack bars have a to

padilas [110]

Answer:

Each glass of milk is 9 carbs.

Each snack bar is 19.7 carbs.

Step-by-step explanation:

1. I know that 2 glasses of milk with 3 snack bars is 78 carbs.

The next part of the sentence has two times the amount of milk with the same amount of snack bars for 96 carbs.

Now, I will find the difference in the amount of carbs.

96 - 78 = 18 carbs.

So two glasses of milk = 18 carbs.

18 ÷ 2 = 9 carbs

So, each glass of milk is 9 carbs.

2. Since we know this, we can subtract the amount of carbs from the glasses of milk from the total amount of carbs.

78 - 19 = 59

In the first scenario, there are 59 carbs per 3 snack bars.

To find the amount of each snack bar, divide 59 by 3.

59 ÷ 3 = 19.7 when rounded to the nearest tenth.

Therefore, each snack bar is 19.7 carbs.

3 0

2 years ago

Read 2 more answers