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Murljashka [212]
3 years ago
14

HELP ME PLEASE

Chemistry
1 answer:
lions [1.4K]3 years ago
3 0

Answer:

A

Explanation:

Definitely not in the cell theory

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The heaviest known isotope of hydrogen is called tritium, . it decays by beta emission, and has a half-life of 12.3 years. what
viva [34]

Answer:

= 3/4

Explanation:

Half life is the time taken by a radioactove element to decay by half of its original mass.

The half life of tritium is 12.3 years , therefore it would take 12.3 years for tritium to decay to a half its original mass.

Using the formula;

New mass = Initial mass × (1/2)^n ; where n is the number of half lives.

n = 5.2 years/12.3 years

  = 52/123

Therefore;

New mass = 1 × (1/2)^(52/123)

                  = 0.74599

                  = 0.75

The fraction of a tritium sample after 5.20 years will be approximately 3/4

6 0
3 years ago
calculate the quantity of 0.001 m aq naoh needed to neutralize the hcl produced by complete solvolysis
abruzzese [7]

The quantity of 0.001 m aq naoh needed to neutralize the hcl produced by complete solvolysis is 200 ml.

Solvolysis is a type of nucleophilic substitution or elimination wherein the nucleophile is a solvent molecule. function of SN1 reactions, solvolysis of a chiral reactant provides the racemate.

Calculation :-

using the titration equation,

M₁V₁ = M₂V₂

substituting values

V₁ = M₂ V₂/M₁

  = 0.2 × 10 ml /0.01

= 2/0.01 ml

= 200 ml.

A reaction in which the solvent is a reactant, and turns into part of the response product. Hydrolysis of tert-butyl chloride; solvent = water. Fischer esterification reaction; solvent = methanol. related phrases: Alcoholysis, aminolysis.

Learn more about solvolysis here:-brainly.com/question/29555642

#SPJ4

<u />

<u>Disclaimer:- your question is incomplete, please see below for the complete question.</u>

Calculate the quantity of 0.01M aq NaOH needed to neutralize the HCl produced by complete solvolysis of the t-BuCl in 10ml of 0.2M t-BuCl in acetone.

5 0
1 year ago
The limiting reactant, O2, can form up to 2.7 mol Al2O3. What mass of Al2O3 forms?
Margaret [11]

Answer:

280 g Al₂O₃

Explanation:

To find the mass, you need to multiply the given value by the molar mass. This will cause the conversion because the molar mass exists as a ratio; technically, the ratio states that there are 101.96 grams per every 1 mole Al₂O₃. It is important to arrange the ratio in a way that allows for the cancellation of units. In this case, the desired unit (grams) should be in the numerator. The final answer should have 2 sig figs to reflect the given value (2.7 mol).

Molar Mass (Al₂O₃): 101.96 g/mol

2.7 moles Al₂O₃          101.96 g
------------------------  x  -------------------  = 275 g Al₂O₃  = 280 g Al₂O₃
                                     1 mole

5 0
2 years ago
What is common to all elements in the same group on the periodic table
marin [14]
They all have the same number of electrons.
3 0
3 years ago
Read 2 more answers
What is the molar mass of a substance?
OlgaM077 [116]

oops pls forgive me I accidentally did the wrong question.

4 0
3 years ago
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