Answer:
please read the answer below
Explanation:
To find the electric field you can consider the Gaussian law for a cylindrical surface inside the slab.
where Qint is the charge inside the Gaussian surface, AG is the area of the surface and rho is the charge density of the slab.
By using the formula for the volume of a cylinder you obtain:
where h is the height. If you assume that the slab is in the interval (-zo<z<z0) you can write VG:
Finally, by replacing in the expression for E you get:
hence, for z>0 you obtain E=pz/eo > 0
for z<0 -> E=pz/eo < 0
Provide the examples again, no samples are presents.
Answer:
W_net = μ 5.58, μ = 0.1 W_net = 0.558 J
Explanation:
The work is defined by the related
W = F. d = F d cos θ
where bold indicates vectors.
In the case, the work of the friction force on a circular surface is requested.
The expression for the friction force is
fr = μ N
the friction force opposes the movement, therefore the angle is 180º and the cos 180 = -1
W = - fr d
the path traveled half the length of the circle
L = 2 π R
d = L / 2
d = π R
we substitute
W = - μ N d
Total work is initial to
W_neto = - μ π R (N_b - N_a)
let's calculate
W_net = - μ π 0.550 (0.670 - 3.90)
W_net = μ 5.58
for the complete calculation it is necessary to know the friction coefficient, if we assume that μ = 0.1
W_net = 0.1 5.58
W_net = 0.558 J
Answer:
relative density is the density divided by some reference density.
for liquids like mercury the reference density is most likely water, so
relative density = density mercury / density of water = 13600
