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3 years ago

Qué tipo de onda tiene mayor velocidad: Onda mecánica en un sólido Onda electromagnética Onda mecánica en el aire

Physics

1 answer:

kogti [31]3 years ago

7 0

Answer:

Onda electromagnética

Explanation:

Las ondas mecánicas requieren un medio material para la propagación, mientras que las ondas electromagnéticas no requieren un medio material para la propagación.

Generalmente, las ondas electromagnéticas se mueven con una velocidad muy alta.

Todas las ondas electromagnéticas se denominan colectivamente luz y tienen una velocidad común de 3 × 10 ^ 8 m / s en el aire.

Ninguna onda mecánica tiene una velocidad tan alta en el aire.

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Which state of matter has the highest density

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Solids have the highest density. Then comes liquid and the less dense one is gas.

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Which one of the following is a derived SI unit? A.newton B.meter C.mole d.Kilogram

marusya05 [52]

Answer:

Meter

Explanation:

I'd say meters, cause it's the SI unit of length,

which is a Derived Quantity.

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4 years ago

A rock is thrown upward from the top of a 30 m building with a velocity of 5 m/s. Determine its velocity (a) When it falls back

castortr0y [4]

Answer:

a) 5 m/s downwards

b) 17.86 m/s

c) 24.82 m/s

d) 0.228

Explanation:

We can set the frame of reference with the origin on the top of the building and the X axis pointing down.

The rock will be subject to the acceleration of gravity. We can use the equation for position under constant acceleration and speed under constant acceleration:

X(t) = X0 + V0 * t + 1/2 * a * t^2

V(t) = V0 + a * t

In this case

X0 = 0

V0 = -5 m/s

a = 9.81 m/s^2

To know the speed it will have when it falls back past the original point we need to know when it will do it. When it does X will be 0.

0 = -5 * t + 1/2 * 9.81 * t^2

0 = t * (-5 + 4.9 * t)

One of the solutions is t = 0, but this is when the rock was thrown.

0 = -5 + 4.69 * t

4.9 * t = 5

t = 5 / 4.9

t = 1.02 s

Replacing this in the speed equation:

V(1.02) = -5 + 9.81 * 1.02 = 5 m/s (this is speed downwards because the X axis points down)

When the rock is at 15 m above the street it is 15 m under the top of the building.

15 = -5 * t + 1/2 * 9.81 * t^2

4.9 * t^s -5 * t - 15 = 0

Solving electronically:

t = 2.33 s

At that time the speed will be:

V(2.33) = -5 + 9.81 * 2.33 = 17.86 m/s

When the rock is about to reach the ground it is at 30 m under the top of the building:

30 = -5 * t + 1/2 * 9.81 * t^2

4.9 * t^s -5 * t - 30 = 0

Solving electronically:

t = 3.04 s

At this time it has a speed of:

V(3.04) = -5 + 9.81 * 3.04 = 24.82 m/s

---------------------

Power is work done per unit of time.

The work in this case is:

L = Ff * d

With Ff being the friction force, this is related to weight

Ff = μ * m * g

μ: is the coefficient of friction

L = μ * m * g * d

P = L/Δt

P = (μ * m * g * d)/Δt

Rearranging:

μ = (P * Δt) / (m * g * d)

1 horsepower is 746 W

20 minutes is 1200 s

μ = (746 * 1200) / (100 * 9.81 * 4000) = 0.228

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3 years ago

Is a truck braking to avoid an accident moving at constant

frutty [35]

Answer:

its not moving at a constant velocity because it is slowing down

Explanation:

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If the pipe of the previous exercise is connected to a hose and the speed there is 3.8 m/s, what is the diameter of the hose?

Amiraneli [1.4K]

The diameter of the hose is 6.34 cm.

"Your question is not complete, it seems to be missing the following information";

the flow rate of water in the pipe is 0.012 m³/s

The given parameters;

velocity of water in the hose, v = 3.8 m/s

flow rate of water in the hose, Q = 0.012 m³/s

Volumetric flow rate is directly proportional to the product of the area of the hose through which the water flows and the velocity of the water flowing through the hose.

Q = Av

where;

Q is the volumetric flow rate

A is the area of the hose

v is the velocity of flow

The area of the hose is calculated as follow;

$A = \frac{Q}{v} \\\\A = \frac{0.012}{3.8} \\\\A = 0.00316 \ m^2$

The diameter of the hose is calculated as follows;

$A = \frac{\pi D^2}{4} \\\\\pi D^2 = 4A\\\\D^2 = \frac{4 \times A}{\pi} \\\\D = \sqrt{\frac{4 \times A}{\pi} } \\\\D = \sqrt{\frac{4 \times 0.00316}{\pi} } \\\\D = 0.0634 \ m\\\\D = 6.34 \ cm$

Thus, the diameter of the hose is 6.34 cm.

Learn more here: brainly.com/question/15061170

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2 years ago