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3 years ago

Qué tipo de onda tiene mayor velocidad: Onda mecánica en un sólido Onda electromagnética Onda mecánica en el aire

Physics

1 answer:

kogti [31]3 years ago

7 0

Answer:

Onda electromagnética

Explanation:

Las ondas mecánicas requieren un medio material para la propagación, mientras que las ondas electromagnéticas no requieren un medio material para la propagación.

Generalmente, las ondas electromagnéticas se mueven con una velocidad muy alta.

Todas las ondas electromagnéticas se denominan colectivamente luz y tienen una velocidad común de 3 × 10 ^ 8 m / s en el aire.

Ninguna onda mecánica tiene una velocidad tan alta en el aire.

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How long would i t take to walk around the eath nonstop?

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Divide (25,000) by (the number of miles you can walk in 1 hour).
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AnnyKZ [126]

Refer to the diagram shown below.

The hoist is in static equilibrium supported by tensions in the two ropes.

For horizontal force balance, obtain
T₃ cos 50 = T₂ cos 38
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Substitute (1) into (2).
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3 years ago

2. A test reveals that 150 J of work is required to lift an object 3 m at a

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Answer:

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2 years ago

When a car is parked in hot sunlight, the temperature of the car’s seats _____ and the thermal energy of the seats _____ .

defon

More info? I think the question is incomplete. Although, I believe the first 2 blanks are "rises"

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3 years ago

Read 2 more answers

A 153 g mass is attached to the end of an unstressed vertical spring (of constant 24.7 N/m) and then dropped. The acceleration o

Arte-miy333 [17]

Answer:

The answer to the question is

Its maximum speed is 1.54 m/s

Explanation:

Work done = Kinetic energy

0.5·m·v² = 0.5·k·x²

Where

m = mass

v = velocity

k = spring constant

x = extension of the spring

We note that Force F is given by

F = m·a

Where

a = acceleration due to gravity

= 0.153×9.8 = 1.4994 N

Equating the work done by the force to the work done on the spring gives

Work done = Force × Distance = 1.4994×x = 0.5×k÷x² = 0.5×24.7×x²

x = 1.4994÷12.35 = 0.121 m

Substituting the value of x into the equation below gives

0.5·m·v² = 0.5·k·x²

0.5×0.153×v² = 12.35×0.121²

v² = 0.182÷0.0765 = 2.379

v = 1.54 m/s

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3 years ago