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Mashcka [7]
3 years ago
8

What do I do if someone is choking me with both of their hands, inside of the classroom and the teacher isn't around? How do I g

et out of their clutches.
Physics
1 answer:
guajiro [1.7K]3 years ago
6 0

Answer:

If you are laying down then nee them in the X.

If you are standing up you gan take them by surprise and give them a hook punch.

Explanation:

Self defenc is very important.

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Answer this question ASAP <br><br>( this is about basketball. )
mixer [17]

Answer:

1. shoot to hard

2. too short

Explanation:

7 0
3 years ago
Read 2 more answers
the gravitational force between two objects is 1600 and what will be the gravitational force between the objects if the distance
Xelga [282]

I believe this is what you have to do:

The force between a mass M and a point mass m is represented by

F = G\frac{Mm}{r^{2} }

So lets compare it to the original force before it doubles, it would just be the exact formula so lets call that F₁

So F₁ = G(Mm/r^2)

Now the distance has doubled so lets account for this in F₂:

F₂ = G(Mm/(2r)^2)

Now square the 2 that gives you four and we can pull that out in front to give

F₂ = \frac{1}{4} G(Mm/r^2)

Now we can replace G(Mm/r^2) with F₁ as that is the value of the force before alterations

now we see that:

F₂ = \frac{1}{4} F₁

So the second force will be 0.25 (1/4) x 1600 or 400 N.



6 0
3 years ago
3m/s for 12 seconds how dar would he walk
Sunny_sXe [5.5K]
I think 36m/12s because 3×12 =36
4 0
3 years ago
A light ray strikes a flat, smooth, reflecting surface at an angle of 80° to the normal. What angle does
charle [14.2K]

Answer:

80 angle of incidence=angle of reflection

Explanation:

7 0
3 years ago
Read 2 more answers
Suppose that you can throw a projectile at a large enough v0 so that it can hit a target a distance R downrange. Given that you
NikAS [45]

Answer:

Theta1 = 12° and theta2 = 168°

The solution procedure can be found in the attachment below.

Explanation:

The Range is the horizontal distance traveled by a projectile. This diatance is given mathematically by Vo cos(theta) t. Where t is the total time of flight of the projectile in air. It is the time taken for the projectile to go from starting point to finish point. This solution assumes the projectile finishes uts motion on the same horizontal level as the starting point and as a result the vertical displacement is zero (no change in height).

In the solution as can be found below, the expression to calculate the range for any launch angle theta was first derived and then the required angles calculated from the equation by substituting the values of the the given quantities.

7 0
3 years ago
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