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3 years ago

Which area of earth is most similar to the suns convention zone

1 answer:

3 0

The area of the Earth that is most similar to the Sun's convection zone would be the mantle. The convection zone of the sun is its outermost layer where heat transfer by convection happens which is similar to the Earth's mantle. It would be the crust because it is the outer most layer.

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what frequency of light must an electron in hydrogen absorb to jump from the n=2 state to the n=5 state? (a) 2.86 Hz (b) 4.08 Hz

Ostrovityanka [42]

Answer:

Explanation:

Find the level energy of n=2 and n=5, using the formula:

$E = -E_0/n^2$

where $E_0=13.6eV$

$E_2 =\frac{-13.6}{2^2}=-3.4eV$

$E_5 =\frac{-13.6}{5^2}=-0.544eV$

To jump from n=2 to n=5 the electron absorbs a photon with energy equal to $(-0.544) - (-3.4)=2.856eV$ , using the next formula to find specific wavelength $\lambda$ to that energy

$E = hc/\lambda$

Where $c$ is the speed of light ( $c=3 \times10^8m/s$ ) and $h$ is Planck's constant ( $h=4.14\times10^{-15}eVs$ ). Solve for $\lambda$ :

$E = hc/\lambda\\\lambda E = hc\\\lambda = \frac{hc}{E} \\\lambda = \frac{(4.14\times10^{-15})(3 \times10^8)}{2.856}=4.35\times10^{-7}m$

The frequency of this wavelength is calculated with this formula:

$f=\frac{c}{\lambda}$

$f=\frac{3\times10^8}{4.3487\times10^{-7}} =6.89\times10^{14}Hz\approx6.9\times10^{14}Hz$

8 0

4 years ago

What is a measure of the consistency and stability of test scores when readministered at different times?

tino4ka555 [31]

Answer:

Reliability is typically shown as a reliability coefficient created in a calculation to determine the reliability, or consistency, of scores, such as a measure of the amount of consistency between two sets of scores from different administrations from the same group of students.

5 0

3 years ago

Distance in scientific notation

n200080 [17]

Answer:

(See explanation for further information)

Explanation:

a) The distances of each planet with respect to the Sun is:

Mercury - $57.909 \times 10^{6}\,mi$

Venus - $67.240\times 10^{6}\,mi$

Earth - $92.960\times 10^{6}\,mi$

Mars - $141.600\times 10^{6}\,mi$

Jupiter - $483.800\times 10^{6}\,mi$

Saturn - $888.200\times 10^{6}\,mi$

Uranus - $1,787\times 10^{6}\,mi$

Neptune - $2,795\times 10^{6}\,mi$

b) The solutions are presented below:

A. The distance between Venus and Jupiter is:

$\Delta s = 483.800\times 10^{6}\,mi-67.240\times 10^{6}\,mi$

$\Delta s = 416.560\times 10^{6}\,mi$

B. The combined distance from the Sun is:

$\Delta s = 57.909\times 10^{6}\,mi + 67.240\times 10^{6}\,mi +92.960\times 10^{6}\,mi$

$\Delta s = 218.109\times 10^{6}\,mi$

Which is less than the distance from the Sun to Neptune ( $2,795\times 10^{6}\,mi$ ).

C. The new distance of Earth is $929.60 \times 10^{6}\,mi$ ( $929,600,000\,mi$ ). Saturn would be the closest planet to Earth, whose distance:

Scientific notation:

$\Delta s = 929.600\times 10^{6}\,mi-888.200\,\times 10^{6}\,mi$

$\Delta s = 41.4\times 10^{6}\,mi$

Standard notation:

$\Delta s = 929,600,000\,mi - 888,200,000\,mi$

$\Delta s = 41,400.000\,mi$

3 0

4 years ago

A guitar string is supposed to have a fundamental frequency 256 Hz. It currently has a fundamental frequency 248 Hz when the str

umka2103 [35]

Answer:

The tension to bring the guitar string into tune is 372.95 Hz.

Explanation:

Given;

current frequency, f₁ = 248 Hz

current tension, T₁ = 350 N

fundamental frequency, f₂ = 256

The tension on the string to bring the guitar string into tune is calculated as;

$v = \sqrt{\frac{T}{\mu} } \\\\f\lambda = \sqrt{\frac{T}{\mu} } \\\\f^2\lambda^2 = \frac{T}{\mu} \\\\f^2 = \frac{T}{\mu \lambda^2}\\\\let \ {\mu \lambda^2} = k\\\\f^2 =\frac{T}{k} \\\\k = \frac{T}{f^2} \\\\\frac{T_1}{f_1^2} = \frac{T_2}{f_2^2}\\\\T_2 = \frac{T_1 f_2^2}{f_1^2} \\\\T_2 = \frac{350 \times 256^2}{248^2} \\\\T_2 = 372.95 \ Hz$

Therefore, the tension to bring the guitar string into tune is 372.95 Hz.

3 0

3 years ago

Which three steps, placed in the proper order, are required for a nuclear chain reaction?.

photoshop1234 [79]

There are three basic steps in a nuclear fission chain reaction are Initiation, Propagation, Termination.

<h3>What are the three steps of nuclear fission ?</h3>

1. Initiation

The nuclear fission of $U_{235} ^{92}$ is started by the absorption of a neutron; a single atom must react in order for the chain reaction to begin.

2. Propagation:-

With each stage producing additional product, this component of the process is repeated repeatedly. When $U_{236} ^{92}$ splits apart, neutrons are released, which start the nuclear fission of more uranium atoms.

3. Termination:

The chain will come to an end eventually. Termination might take place if the reactant $U_{235} ^{92}$ is exhausted or if the subsequent neutrons in the chain leave the sample without being absorbed by $U_{235} ^{92}$ .

To learn more about nuclear fission with the given link

brainly.com/question/913303

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3 0

2 years ago