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Ilia_Sergeevich [38]
2 years ago
12

If the population runs out of food after 6 hours, what would most likely happen to the graph line between 8 and 10 hours?

Physics
2 answers:
Radda [10]2 years ago
5 0
It would decline since the population is out of food
padilas [110]2 years ago
3 0
It would decrease because there is no more food
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A ball is released from a hot air balloon moving downward with a velocity of -10.0 meters/second and a height of 1,000 meters. H
Nikolay [14]
Here, ball is released... and it is in free fall means with zero initial velocity.

We know, s = ut + 1/2 at²
Here, s = 1000 m
u = 0
a = 10 m/s2

Substitute their values, 
1000 = 0 + 1/2 * 10 * t²
2000 = 10 * t²
t² = 2000 /10
t = √200
t = 14.14 s

In short, Your Answer would be 14.14 seconds

Hope this helps!
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A bowling lane is 18 meters long. How long would it take a 1.5 m/s bowling ball to
lara31 [8.8K]

Divide distance by speed:

18 meters / 1.5 meters/ second = 12 seconds

Answer: 12 seconds

5 0
2 years ago
please help me with my question I will like and mark as brainliest NO LINKS THEY DON'T WORK AND IF U DON'T KNOW THE ANSWER PLS D
bearhunter [10]

Answer:

a)

Weight in Air = 0.3N

Weight in Water = 0.25N

Weight in Liquid = 0.24N.

Upthrust /Buoyant Force = Weight in Air – Weight in Fluid(Water in this case)

= 0.3 – 0.25

= 0.5N.

b) R.D of Body = Density of Body/Density of Standard Fluid(Water).

There's a Derived Formula for RD.

I'm gonna Apply it here.

Ask me for the derivation in the Comment section if you need it.

RD = α/ρ = (Weight in Air) / (Upthrust Force)

Where

α = density of the Body(or reference substance)

ρ = density of standard fluid (water)

= 0.3/0.05 = 6.

c) RD of Liquid = (Density of Liquid) /(Density of standard Fluid(water)

Or we just go by that formula

RD of Liquid = Weight in Air/Upthrust(In Liquid)

We'll be using the Upthrust in that Liquid now.

= 0.3 – 0.24 = 0.06

RD = 0.3/0.06 = 5.

7 0
2 years ago
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