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7nadin3 [17]
3 years ago
11

A 9.03 g sample of magnesium reacts completely with 3.48 g of nitrogen to form a compound of

Chemistry
1 answer:
hjlf3 years ago
8 0

Answer:

12.5 g

Explanation:

<em>12.5 g of the compound would be formed.</em>

First, let us look at the balanced equation of reaction.

3 Mg(s) + N_2(g) --> Mg_3N_2(s)

3 moles of Mg is required to react with 1 mole of N2 to produce 1 mole of product.

<em>Recall that: mole = mass/molar mass</em>

9.03 g of Mg = 9.03/24.3 = 0.3716 mole

3.48 g of N2 = 3.48/28 = 0.1243 mole

Mole ratio of Mg/N2 = 3:1

<em>Hence, there is no limiting reactant.</em>

3 moles of Mg is required for 1 mole of product.

0.3716 mole of Mg will therefore require:

       0.3716 x 1/3 = 0.1239 moles of product.

Molar mass of product Mg_3N_2 = 100.9 g/mol

Mass of 0.1239 mole Mg_3N_2 = mole x molar mass

                      = 0.1239 x 100.9 = 12.5 g

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2H₂₍g₎ + O₂ ₍g₎→ 2H₂O

138 mol H₂ × (2 mol H₂O ÷ 2 mol H₂)= 138 mol H₂O
64 mol O₂ × (2 mol H₂O ÷ 1 mol O₂)= 128 mol H₂O

128 mol H₂O
6 0
4 years ago
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3 years ago
Suppose you have 75 gas-phase molecules of methanol (CH3OH) at T = 470 K. These molecules are contained in a spherical container
Katarina [22]

Answer:

The average pressure in the container due to these 75 gas molecules is P=9.72 \times 10^{-16} Pa

Explanation:

Here Pressure in a container is given as

P=\frac{1}{3} \rho

Here

  • P is the pressure which is to be calculated
  • ρ is the density of the gas which is to be calculated as below

                                         \rho =\frac{mass}{Volume of container}

        Here

                mass is to be calculated for 75 gas phase molecules as

                      m=n_{molecules} \times \frac{1 mol}{6.022 \times 10^{23} molecules} \times \frac{32 g/mol}{1 mol}\\m=75 \times \frac{1 mol}{6.022 \times 10^{23} molecules} \times \frac{32 g/mol}{1 mol}\\m=3.98 \times  10^{-21} g

              Volume of container is 0.5 lts

     So density is given as

                         \rho =\frac{mass}{Volume of container}\\\rho =\frac{3.98 \times 10^{-21} \times 10^{-3} kg}{0.5 \times 10^{-3} m^3}\\\rho =7.97 \times 10^{-21}\, kg/m^3

  • is the mean squared velocity which is given as

                                        =RMS^2

      Here RMS is the Root Mean Square speed given as 605 m/s so

                                      =RMS^2\\=(605)^2\\=366025

Substituting the values in the equation and solving

P=\frac{1}{3} \rho \\P=\frac{1}{3} \times 7.97 \times 10^{-21} \times 366025\\P=9.72 \times 10^{-16} Pa

So the average pressure in the container due to these 75 gas molecules is P=9.72 \times 10^{-16} Pa

6 0
4 years ago
How many grams of F− must be added to a cylindrical water reservoir having a diameter of 2.02 × 102 m and a depth of 87.32 m?
aksik [14]

Complete Question:

To aid in the prevention of tooth decay, it is recommended that drinking water contain 0.800 ppm fluoride. How many grams of F− must be added to a cylindrical water reservoir having a diameter of 2.02 × 102 m and a depth of 87.32 m?

Answer:

2.23x10⁶ g

Explanation:

The concentration of the fluoride (F⁻) must be 0.800 ppm, which is 0.800 parts per million, so the water must have 0.800 g of F⁻/ 1000000 g of the solution. The density of the water at room temperature is 997 kg/m³ = 997x10³ g/m³. So, the concentration of the fluoride will be:

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m = 0.7976 * 2.7983x10⁶

m = 2.23x10⁶ g

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After the dillution of the solution, the wavelength of maximum absorption is decreased.

<h3>What is the wavelength of maximum absorption?</h3>

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When the starting concentration of the  K2Cr2O7 is diluted, the wavelength of maxium absorption decreases.

Learn more about maximum absorption: brainly.com/question/26610701

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