Emf e = 11
r 1 = 3.0
r 2 = 3.0
r 3 = ?
The two in parallel are equivalent to 3 • 3/6 = 1.5 Ω
To have 2.4 volts across them, the current is I = 2.4/1.5 = 1.6 amps. and the unknown R = (11–2.4) / 1.6 = 5.375 Ω or 5.4 Ω
Answer: 1/R = 1/r1 + 1/r2 + 1/r3
Explanation:
Just did the test myself. Hope this helps!
No Solution:
4x+10y = 40
2x + 5y = 40
2x - 8y=17
x - 4y = 7
One Solution:
2y - X= 12
2y - 2x =10
x + 10y =50
2x + 10y =90
Infinitely Many Solutions:
x + 2y = 1
3x + 6y= 3
2y - 3x = 5
2/5y -3/5x =1
Explanation: You only had 11 equations listed. But I believe these are the ones you want. I took the test and got them right. Hope it helps
Answer:19.5 J
Explanation:
Given
mass of block=3 kg
angular frequency=20 rad/sec
spring constant 
we know total energy remain conserved
Where 
=kinetic energy
=potential Energy
When mass reaches amplitude its velocity becomes zero
there is only potential energy which is equal to Total energy
Answer
given,
Weight of the child = 110 N
length of the swing,L = 2 m
now, calculating the potential energy when the string is horizontal
Potential energy = m g h
now, h = L (1 - cos θ) where θ is the angle made by the string with the vertical.
PE = m g L (1 - cos θ)
when rope is horizontal θ = 90°
PE = 110 x 2 (1 - cos 90°)
PE = 220 J
now, calculating potential energy when string made 25° with horizontal
PE = m g L (1 - cos θ)
when rope is horizontal θ = 25°
PE = 110 x 2 (1 - cos 25°)
PE = 20.61 J
