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Sati [7]
2 years ago
13

A 325 g iron bucket contains 527 g of water, both at 21.6°C. A 855 g piece of hot steel (T = 352 degrees Celsius) is added to bu

cket at the same time 295 g of ice at -22.2°C is added. Determine if all the ice melts. If so, what is the final temperature of the mixture? If not, how much of the ice melted?
Physics
1 answer:
Neporo4naja [7]2 years ago
3 0

Answer:

T = 18.63 ^oC

Explanation:

As we know that heat given by the hot piece of iron = heat absorbed by water + ice

As we know that

c_{iron} = 0.450 J/g ^oC

also we have

c_{ice} = 2050 J/kg ^oC

now we have

325(0.450)(T-21.6) + 0.527(4186)(T - 21.6) + 0.295(2050)(0 + 22.2) + (0.295)(335000) + 0.295(4186)(T - 0) = 855(0.450)(352 - T)

146.25T - 3159 + 2206T - 47650 + 13425.45 + 98825 + 1234.87T = 135432 - 384.75 T

3971.87 T = 73990.55

T = 18.63 ^oC

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