Answer- 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
Given - Number of moles of Al(NO3)3 - 4 moles
Number of moles of NaCl - 9 moles
Find - Maximum amount of AlCl3 produced during the reaction.
Solution - The complete reaction is - Al(NO3)3 + 3NaCl --> 3NaNO3 + AlCl3
To find the maximum amount of AlCl3 produced during the reaction, we need to find the limiting reagent.
Mole ratio Al(NO3)3 - 4/1 - 4
Mole ratio NaCl - 9/3 - 3
Thus, NaCl is the limiting reagent in the reaction.
Now, 3 moles of NaCl produces 1 mole of AlCl3
9 moles of NaCl will produce - 1/3*9 - 3 moles.
Weight of AlCl3 - 3*133.34 - 400 grams
Thus, 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
In order to balance out the Electrons, and give it a net charge of 0, you would need 79 Protons.
Before you begin titration, drops of indicator are added to the Erlenmeyer flask. This happens when preparing to measure pH change.
Answer:
= 2.94 atm
Explanation:
The total pressure () in the container is given by:
The pressure of the oxygen (
) and the pressure of the helium (
) can be calculated using the ideal gas law:
<u>Where</u>:
V: is the volume = 25.0 L
n: is the number of moles of the gases
R: is the gas constant = 0.082 Latm/(Kmol)
T: is the temperature = 298 K
First, we need to find the number of moles of the oxygen and the helium:
Where m is the mass of the gas and M is the molar mass
And the number of moles of helium is:
Now, we can find the pressure of the oxygen and the pressure of the helium:
Finally, the total pressure in the container is:
Therefore, the total pressure in the container is 2.94 atm.
I hope it helps you!
The time taken for the isotope to decay is 46 million years.
We'll begin by calculating the number of half-lives that has elapsed. This can be obtained as follow:
- Original amount (N₀) = 50.25 g
- Amount remaining (N) = 16.75
- Number of half-lives (n) =?
2ⁿ = N₀ / N
2ⁿ = N₀ / N
2ⁿ = 50.25 / 16.75
2ⁿ = 3
Take the log of both side
Log 2ⁿ = 3
nLog 2 = Log 3
Divide both side by log 2
n = Log 3 / Log 2
n = 2
Finally, we shall determine the time.
- Half-life (t½) = 23 million years
- Number of half-lives (n) = 2
t = n × t½
t = 2 × 23
t = 46 million years
Learn more about half-life: brainly.com/question/25927447
