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3 years ago

Which of the following is equal to square root 9•16

Mathematics

1 answer:

natulia [17]3 years ago

4 0

Answer:

Letter B

9.16

...........

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I am a number between 200 and 2006.I am odd and divisible by 3. What number am I?

Mashcka [7]

Answer: 201 is the correct answer

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3 years ago

What is the value of y in the equation 4(5y − 8 − 2) = 185 − 15? 8. 5 9. 7 10. 5 42. 5.

Bezzdna [24]

Answer:

10.5 is the answer

Step-by-step explanation:

4(5y−8−2)=185−15

(4)(5y)+(4)(−8)+(4)(−2)=185+−15(Distribute)

20y+−32+−8=185+−15

(20y)+(−32+−8)=(185+−15)(Combine Like Terms)

20y+−40=170

20y−40=170

20y−40+40=170+40

20y=210

20y/20=210/20

y=21/2

y=10.5

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2 years ago

33. Which side of the triangle in the diagram is the hypotenuse?<br> A. B<br> B. C<br> C. A

Alik [6]

The answer is option B, if this helped mark me the brainiest!!

4 0

3 years ago

Read 2 more answers

Bruh can someone answer this I’ll give brainliest

3241004551 [841]

It’s a ! you add both of the numbers to get your missing perimeter.
I’m very sorry if it’s wrong but this is what I believe! stay safe

4 0

3 years ago

Multiply.

Nady [450]

$\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}$

<h2>Explanation:</h2>

Here we have the following expression:

$3\sqrt{22}\sqrt{58}\sqrt{18}$

So we need to simplify that radical expression. By property of radicals we know that:

$\sqrt[n]{a}\sqrt[n]{b}=\sqrt[n]{ab}$

So:

$3\sqrt{22}\sqrt{58}\sqrt{18}=3\sqrt{22\times 58 \times 18}=3\sqrt{22968}$

The prime factorization of 22968 is:

$22968=2^3\cdot 3^2\cdot11\cdot 29$

Hence:

$3\sqrt{22968}=3\sqrt{2^3\cdot 3^2\cdot11\cdot 29}=3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29}$

By property:

$\sqrt[n]{a^n}=a$

So:

$3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29} \\ \\ 3(2)(3)\sqrt{2\cdot 11\cdot 29}=18\sqrt{638}$

Finally:

$\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}$

<h2>Learn more:</h2>

Radical expressions: brainly.com/question/13452541

#LearnWithBrainly

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3 years ago