Answer:
We'll have 1.00 mol H2
Explanation:
Step 1: Data given
Number of moles of Mg = 1.00 moles
Step 2: The balanced equation
Mg(s) + H2SO4(aq) → MgSO4(aq) + H2(g)
Step 3: Calculate moles of H2
For 1 mol Mg we need 1 mol H2SO4 to produce 1 mol MgSO4 and 1 mol H2
We'll have 1.00 mol H2
Answer:
B
Explanation:
Firstly, we will need to calculate the number of moles. To do this, we make use of the ideal gas equation
PV = nRT
n = PV/RT
The parameters have the following values according to the question:
P = 780mmHg, we convert this to pascal.
760mHG = 101325pa
780mmHg = xpa
x = (780 * 101325)/760 = 103,991 Pa
V= 400ml = 0.4L
T = 135C = 135 + 273.15 = 408.15K
n = ?
R = 8314.463LPa/K.mol
Substituting these values into the equation yields the following:
n = (103991 * 0.4)/(8314.463 * 408.15)
= 0.012 moles
Now we know 1 mole contains 6.02 * 10^23 molecules, hence, 0.012moles will contain = 0.012 * 6.02 * 10^23 = 7.38 * 10^21 molecules
Yes, it can - HBr is its chemical formula.
If you had other options though, then the one which wouldn't be a valid chemical formula is aluminum (III) chloride, because, since it only has one charge (+3), it is unnecessary to state it as III.
Bromine, it's the only element that isn't a metal
