Answer:
pressure of the oxygen gas is 7.88atm
Explanation:
Moles of oxygen in cylinder = 2.80 mol
volume=8.58L
temperature=294K
molar gas constant(R)= 0.0821 L atm / (mol K)
The pressure is calculated using ideal gas law:
PV = nRT
making Pressure subject of the formula
P
=
nRT
/V
=
2.80× 0.0821 ×294 /8.58 L
P = 7.88 atm
Answer:
The tabulated values at 120 C of <u><em>hfg = 2202.1</em></u><u> kJ/Kg </u>and <u><em>sfg </em></u><u>= 5.6 </u>
<u>kJ/Kg.K</u>
Explanation:
According to Clapeyron Equation :
Taking P2 at temperature 125 and P1 at 115 degree Celsius .
T = 120 + 273.15 = 393.15 K
P2 = 232.23 kPa and P1 = 169.18kPa
(these are experimental values given in the Data)
= 5.6131 kJ/Kg.K
The tabulated values at 120 C of <em>hfg = 2202.1</em> kJ/Kg and <em>sfg </em>= 5.6131
kJ/Kg.K
Answer: The energy of a photon with a wavelength of 820 nm is .
Explanation:
Given : Wavelength = 820 nm
Convert nm into meter as follows.
The relation between energy and wavelength is as follows.
where,
E = energy
h = Planck's constant =
c = speed of light =
= wavelength
Substitute the values into above formula as follows.
Thus, we can conclude that energy of a photon with a wavelength of 820 nm is .
Answer : The concentration of AB after 14.0 s is, 0.29 M
Explanation :
The expression used for second order kinetics is:
where,
k = rate constant =
t = time = 14.0 s
= final concentration = ?
= initial concentration = 1.50 M
Now put all the given values in the above expression, we get:
Therefore, the concentration of AB after 14.0 s is, 0.29 M