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Naddika [18.5K]
3 years ago
8

A piece of iron is heated with a torch to a temperature of 603 k.

Chemistry
1 answer:
Mazyrski [523]3 years ago
5 0
This question asks to compare the energy emitted by a piece of iron at T = 603K with the energy emitted by the same piece at T = 298K.

Then you need to use the Stefan–Boltzmann Law

That law states that energy emitted (E) is proportional to fourth power of the  to the absolute temperature (T), this is E α T^4 (the sign α is used to express proportionallity.

Then E (603) / E (298) = [603K / 298K]^4 = 16,8

Which meand that the Energy emitted at 603 K is 16,8 times the energy emitted at 298K.


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A sample of glucose contains 1.250x10^21 carbon atoms, how many atoms of hydrogen does it contain?
dybincka [34]

Answer:

Hydrogen = 2.5 * 10^21

Explanation:

Chemical Formula Glucose: C₆H₁₂O₆

One of the ways you could do  this is to notice that for every carbon atom there are two Hydrogen atoms. You can state this more formally by using the formula to set up a ratio: 12/6 = hydrogen to Carbon

So if there are 1.250 * 10^21 Carbon atoms in the Glucose sample, then there will be twice as many hydrogen atoms.

H = 2 * 1.25 * 10^21 = 2.5 * 10^21 atoms

You could do this more formally by setting up a proportion.

6 Carbon / 12 Hydrogen = 1.25*10^21 /  x         Cross Multiply

6*x = 12 * 1.25*10^21                                           Combine the right

6x = 1.5 * 10^22                                                  Divide by 6

x = 2.5 * 10^21

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2 years ago
Which property controls the movement of groundwater by determining the rate at which water passes through the soil?
Dimas [21]

The answer is permeability

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3 0
3 years ago
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Which of the following is a unit of volume in the metric system? (5 points)
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Convert the following measurements using dimensional analysis. Set up problem using factors. Cross out the units that cancel. YO
uranmaximum [27]

Answer:

1) 0.423 m

2) 3.107 mi

3) 68.18 kg

4) 0.0083 mem

5) 0.528 gal

6) 4300 mL

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Explanation:

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3 years ago
A cylinder of argon contains 50 L of Ar at 12.4 atm and 127°C . How many moles of argon are in the cylinder
joja [24]

Answer:

18.9 moles

Explanation:

We have the following data:

V = 50 L

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We use the ideal gas equation to calculate the number of moles n of the gas:

PV = nRT

⇒ n = PV/RT = (12.4 atm x 50 L)/(0.082 L.atm/K.mol x 400 K) = 18.9 mol

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