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3 years ago

Tetraphosphorous decoxice (P4O10) reacts with water to produce phosphoric acid.

Chemistry

1 answer:

Shkiper50 [21]3 years ago

5 0

Answer:

1) P4O10 + 6H20 → 4H3PO4

2) 1.25 moles of P4O10

3) 7.5 moles of water

Explanation:

1. Write the balanced equation for this reaction

P4O10 + 6H20 → 4H3PO4

2) Determine the number of moles of P4O10 required to produce 5.00 moles of phosphoric acid.

For 1 mole P4O10 consumed, we need 6 moles of water to produce 4 moles of H3PO4

If we get 5.00 moles of H3PO4, we'll have 5/4 = 1.25 moles of P4O10 consumed.

3) Determine the number of moles of water required to produce 5.00 moles of phosphoric acid

For 1 mole P4O10 consumed, we need 6 moles of water to produce 4 moles of H3PO4

If we have 5.00 moles of H3PO4, we'll get (6/4)*5 = 7.5 moles of water consumed.

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a. Kp=1.4

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Explanation:

For the reaction

A(g)⇌2B(g)

Kp is defined as:

$Kp=\frac{(P_{B})^{2}}{P_{A}}$

The conditions in the system are:

A B

initial 0 1 atm

equilibrium x 1atm-2x

At the beginning, we don’t have any A in the system, so B starts to react to produce A until the system reaches the equilibrium producing x amount of A. From the stoichiometric relationship in the reaction we get that to produce x amount of A we need to 2x amount of B so in the equilibrium we will have 1 atm – 2x of B, as it is showed in the table.

Replacing these values in the expression for Kp we get:

$Kp=\frac{(1-2x)^{2}}{x}$