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4 years ago

Tetraphosphorous decoxice (P4O10) reacts with water to produce phosphoric acid.

Chemistry

1 answer:

Shkiper50 [21]4 years ago

5 0

Answer:

1) P4O10 + 6H20 → 4H3PO4

2) 1.25 moles of P4O10

3) 7.5 moles of water

Explanation:

1. Write the balanced equation for this reaction

P4O10 + 6H20 → 4H3PO4

2) Determine the number of moles of P4O10 required to produce 5.00 moles of phosphoric acid.

For 1 mole P4O10 consumed, we need 6 moles of water to produce 4 moles of H3PO4

If we get 5.00 moles of H3PO4, we'll have 5/4 = 1.25 moles of P4O10 consumed.

3) Determine the number of moles of water required to produce 5.00 moles of phosphoric acid

For 1 mole P4O10 consumed, we need 6 moles of water to produce 4 moles of H3PO4

If we have 5.00 moles of H3PO4, we'll get (6/4)*5 = 7.5 moles of water consumed.

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PLS HELP - How many moles are present in 3.01 x 1023 atoms of N2 (nitrogen gas) ?

Neporo4naja [7]

Answer:

<h2>0.5 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{3.01 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{3.01}{6.02} = 0.5 \\$

We have the final answer as

<h3>0.5 moles </h3>

Hope this helps you

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3 years ago

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ivanzaharov [21]

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3 years ago

The Nernst equation at 20oC is:

saw5 [17]

Answer:

a. -58 millivolts

Explanation:

The given Nernst equation is:

$E_{ion} = 58 millivolts /z \Big[ log_{10} \Big( \dfrac{[ion]_{out}}{[ion]_{in}}\Big) \Big]}$

The equilibrium potential given by the Nernst equation can be determined by using the formula:

$E_{Cl^-} = \dfrac{2.303*R*T}{ZF} \times log \dfrac{[Cl^-]_{out}} {[Cl^-]_{in}}$

where:

gas constant(R) = 8.314 J/K/mol

Temperature (T) = (20+273)K

= 298K

Faraday constant F = 96485 C/mol

Number of electron on Cl = -1

$E_{Cl^-} = \dfrac{2.303*8.314*298} {(-1)*(96845)} \times log \dfrac{100} {10}$

$E_{Cl^-} = - 0.05814 \ volts$

$\mathsf{E_{Cl^-} = - 0.05814 \times 1000 \ milli volts}$

$\mathsf{E_{Cl^-} \simeq - 58\ milli volts}$

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3 years ago

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8090 [49]

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In comparison to other given substances, n-butane has the weakest dispersion forces. Thus, n-butane has lowest surface tension.

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3 years ago

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Katarina [22]

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3 years ago

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