4 years ago

Fill in the blank. 5.22x10^-3 = [? ]x 10^-2

Chemistry

1 answer:

andrew-mc [135]4 years ago

6 0

Answer:

?=0.522

Explanation:

5.22*10^-3=?*10^-2

5.22*0.01=?*0.1

0.522=?

This is my first time answer question, thx!

You might be interested in

What are the two main ways that minerals are classified

Kazeer [188]

country of origin and chemical makeup

3 0

3 years ago

Oxygen gas is generated in the laboratory by the thermal decomposition of potassium chlorate what volume of oxygen is generated

Kruka [31]

The answer is 2 potassium

8 0

3 years ago

A sample of unknown hydrate, AC-XH20, has a mass of 1.000 g before heating and a

KIM [24]

Answer:

The water of crystallization for the formula of the unknown hydrate is 2.

Explanation:

Mass of an unknown hydrate = 1.000 g

Molar mass of hydrate = 195.5 g/mol

MOles of unknown hydrate = $\frac{1.000 g}{195.5 g/mol}=0.00512 mol$

Mass of hydrate after heating = 0.781 g

Mass of water lost due to heating = x

$1.000 g = 0.781 g + x\\x = 1.000 g - 0.781 g = 0.219 g$

Moles of water lost = $\frac{0.219 g}{18.01528 g/mol}=0.0122 mol$

$AC.xH_2O+Heat\rightarrow AC+xH_2O$

1 Mole of hydrate has x moles of water and 0.00512 moles of hydrate has 0.0122 moles of water then we can write:

$\frac{1 }{x}=\frac{0.00512 }{0.0122 }\\x\approx 2$

The water of crystallization for the formula of the unknown hydrate is 2.

7 0

3 years ago

What is the potential energy of a car with a mass of 1200kg at the top of a 42m high hill?

GalinKa [24]

Answer:

P.E = 493920 j

Explanation:

Given data:

Mass = 1200 kg

height = 42 m

Potential energy = ?

Solution:

Formula:

Now we will put the values in formula.

g = 9.8 m/s²

P.E = 1200 Kg × 9.8 m/s²× 42 m

P.E = 493920 Kg.m²/s²

Kg.m²/s² = j

P.E = 493920 j

8 0

4 years ago

3 H2S + 2 HNO3 +35 + 2 NO + 4 H2O

Anettt [7]

Element Oxidized: S (S^(2-) --> S⁰)

Element Reduced: N (N^(5+) --> N(2+))

Oxidizing Agent: HNO3

Reducing Agent: H2S

3 0

3 years ago