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valentina_108 [34]
3 years ago
13

An hydraulic cylinder has a piston diameter of 150mm and strokes at 300mm in 10 seconds. Calculate- A) The swept volume of the a

ctuator in liters B) The pump displacement in Liters/minute
Engineering
1 answer:
SOVA2 [1]3 years ago
5 0

Answer:

(a)Volume in liters=5.3 liters.

(b)Volume in liters/minute=31.8 liters/minute.

Explanation:

Given:  

   Diameter of cylinder ,D=150 mm

                         Stroke,L=300 mm

                         Time ,t=10 sec

we know that swept volume of cylinder

          V_{s}=\dfrac{\pi }{4}\times D^2\times L

So V_{s}=\dfrac{\pi }{4}\times 0.15^2\times 0.3 m^{3}

     V_{s}=0.0053 m^3

(a) Volume in liters =5.3 liters         ( 1m^3=1000 liters)

(b) When we divide swept volume  by time(in minute) we will get liters/minute.

 We know that 1 minute=60 sec

⇒10 sec=\frac{10}{60} minute

So volume displace in liters/minute=31.8 liters/minute.

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An escalator in a shopping center is designed to move 50 people, 75 kg each, at a constant speed of 0.6 m/s at 450 slope. Determ
REY [17]

Answer:

Power required to drive the escalator shall be equal to the rate at which the energies of the persons is increased.

Energy=n\times mass\times g\times h\\\\\therefore Power=n\times mass\times g\times \frac{dh}{dt}\\\\Power=50\times 75\times 9.81\times 0.6sin(45)\\\\Power=15.607kW

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A 75 mm diameter, 15 mm wide A80-M12V grinding wheel is used for traverse surface grinding of a 75 mm by 75 mm 1040 steel workpi
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3 years ago
Under EPA's regulations, which of the following methods can be used to pressurize an R11 or R123 system for the purpose of openi
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Answer:

(A) Adding Nitrogen

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7 0
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4.In a hydroelectric power plant, 100 m3/s of water flows from an elevation of 120 m to a turbine, where electric power is gener
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Answer:

The rate of irreversible loss will be "55.22 MW".

Explanation:

The given values are:

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h = 120 m

Flow of water,

Q = 100 m³/s

Efficiency,

= 80%

i.e,

= 0.8

Efficiency turbine,

= 50 MW

Now,

Without any loss,

The power generated by turbine will be:

⇒ P=\delta gQh

On substituting the values, we get

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⇒     =117.72 \ MW

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= \frac{50}{0.8}

= 62.5 \ MW

Hence,

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= Power \ generated \ by \ turbine-Power \ generated  \ in \ actual

= 117.72-62.5

= 55.22 \ MW

4 0
3 years ago
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