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Hunter-Best [27]
4 years ago
14

A balloon of air now occupies 5.0 L, at 25 celcius and 1.00 atm. What temperature was it initially, if it occupied 4.0 L and was

in a very cold freezer with a pressure of 0.92 atm?
combined gas laws
A. 219k B. 298k C.325k D.425k
Chemistry
1 answer:
xenn [34]4 years ago
5 0

Answer: A. 219K

Explanation:

Using the Combined Gas Law; P1 V1/T1 = P2V2/T2

Where P1 = 0.92 atm, P2 = 1.00 atm

           V1 =4.0 L,   V2 = 5.0 L

           T1 =  ?,  T2 = 25 celcius = 298K

We therefore make T1 the subject of the formular;

T1 = P1 . V1 .T2 / P2. V2

    = 0.92atm x 4.0L x 298K / 1.00 atm x 5.0 L

    = 1096.64 /   5

    = 219.328 approx  219K

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pshichka [43]
Data:

<span>Solute: 28.5 g of glycerin (C3H8O3)
Solvent: 135 g of water at 343 k.
Vapor pressure of water at 343 k: 233.7 torr.

Quesiton: Vapor pressure of water

Solution:

Raoult's Law: </span><span><span>The vapour pressure of a solution of a non-volatile solute is equal to the vapour pressure of the pure solvent at that temperature  multiplied by its mole fraction.

Formula: p = Xsolvent * P pure solvent

X solvent = moles solvent / moles of solution

molar mass of H2O = 2*1.0g/mol + 16.0 g/mol = 18.0 g/mol

moles of solvent = 135 g of water / 18.0 g/mol = 7.50 mol

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Answer: 224.4 torr
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3 years ago
How many grams of calcium carbonate were used if you drew the periodic table on the sidewalk using
german

Based on the data provided, there are 25 g of calcium carbonate in 1.505 × 10^23 atoms.

<h3>What is the moles of calcium carbonate in 1.505 × 10^23 atoms of calcium carbonate?</h3>

The mole of a substance can be calculated as follows:

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Learn more about molar mass and mass at: brainly.com/question/15476873

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Answer:

See the answer below

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