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3 years ago

10

bro can ya'll like not delete my questions if i say to jus talk? like ya'll clowns nd need to get a life like es 2021 y realment

e quieres ser un payaso. está bien. tu lo haces tu. :)

1 answer:

kompoz [17]3 years ago

8 0

Answer:

Es casi como si este sitio se utiliza para responder preguntas académicas, no para ch/atear ocioso

Explanation:

:)

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What is the pH of a KOH solution that has [H ] = 1. 87 × 10–13 M? What is the pOH of a KOH solution that has [OH− ] = 5. 81 × 10

vlada-n [284]

pH is the hydrogen ion concentration and pOH is the hydroxide ion concentration in the solution. pH KOH is 12.73, pOH KOH is 2.24 and pH NaCl is 7.

<h3>What are pH and pOH?</h3>

pH is the negative log of the hydrogen ion concentration and pOH is the negative log of the hydroxide ion concentration.

The relation between the pH and pOH can be given as, $\rm pOH = 14 - pH$

The pH of KOH can be calculated by the formula,

$\rm pH = \rm -log [H^{+}]$

In the first case, the concentration of the KOH is $1. 87 \times 10^{-13}\;\rm M$

Substituting values in the equation:

$\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 87 \times 10^{-13}\;\rm M ]\\\\&= 12.73\end{aligned}$

Hence, the pH of KOH is 12.73.

<u />

pOH of KOH can be calculated by the formula,

$\rm pOH = \rm -log [OH^{-}]$

The hydroxide concentration of the KOH solution is $5. 81 \times 10^{-3}\;\rm M$

Substituting value in the equation:

$\begin{aligned} \rm pOH &= \rm -log [OH^{-}]\\\\&= \rm -log [5. 81 \times 10^{-3}\;\rm M ]\\\\&= 2.24 \end{aligned}$

Hence, the pOH of KOH is 2.24

<u />

The pH of NaCl can be calculated by the formula,

$\rm pH = \rm -log [H^{+}]$

In the third case, the concentration of the NaCl is $1. 00\times 10^{-7}\;\rm M$

Substituting values in the equation:

$\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 00 \times 10^{-7}\;\rm M ]\\\\&= 7 \end{aligned}$

Hence, the pH of KOH is 7.0.

Therefore, KOH is basic and NaCl is approximately neutral.

Learn more about pH and pOH here:

brainly.com/question/13885794

3 0

2 years ago

A 3.8-mol sample of KClO3 was decomposed according to the equation. How many moles of O2 are formed assuming 100% yield?

kari74 [83]

Answer:

5.7 moles of O2

Explanation:

We'll begin by writing the balanced decomposition equation for the reaction. This is illustrated below:

2KClO3 —> 2KCl + 3O2

From the balanced equation above,

2 moles of KClO3 decomposed to produce 3 moles of O2.

Next, we shall determine the number of mole of O2 produced by the reaction of 3.8 moles of KClO3.

Since 100% yield of O2 is obtained, it means that both the actual yield and theoretical yield of O2 are the same. Thus, we can obtain the number of mole of O2 produced as follow:

From the balanced equation above,

2 moles of KClO3 decomposed to produce 3 moles of O2.

Therefore, 3.8 moles of KClO3 will decompose to produce = (3.8 × 3)/2 = 5.7 moles of O2.

Thus, 5.7 moles of O2 were obtained from the reaction.

3 0

3 years ago

Classify the following as a solution, suspension or colloid

frosja888 [35]

Answer:

Solution - (a) Brine . Suspension - (c) sand and water, (g) chalk and water Colloid - (e) air, (f) smoke , (d) soda , (b) milk

Explanation:

A solution is an homogeneous mixture of two or more compounds.

A suspension is a heterogeneous mixture of two or more compounds while a colloid is a homogeneous mixture of two or more compounds with suspended particles which do not settle.

So, under these definitions, the classifications are as follows-

Solution - (a) Brine .

Suspension - (c) sand and water, (g) chalk and water

Colloid - (e) air, (f) smoke , (d) soda , (b) milk

6 0

3 years ago

What conversion factor is present in almost all stoichiometry calculations?

luda_lava [24]

<h3><u>Answer;</u></h3>

Molar mass

<h3><u>Explanation</u>;</h3>

Stoichiometry involves the study of quantitative relationships between the amounts of reactants used and products formed by a chemical reaction.
A conversion factor is a ratio of coefficients found in a balanced reaction, which can be used to inter-convert the amount of products and reactants.
Molar ratios, or conversion factors, identify the number of moles of each reactant needed to form a certain number of moles of each product.

8 0

3 years ago

How many moles of H2O can be produced with 5.8 moles of O2 ?

Evgesh-ka [11]

Answer:

1.78

Explanation:

1mole produce 18g/x will produce 32g then the answer is 1.78moles

8 0

3 years ago