A pH of 3 is acidic! hope this helps:)
a pH of 0-6 is acidic
a pH of 7 is neutral
a pH of 8-14 is basic
5 protons in the boron nucleus
Answer:
Answer is A
Explanation:
Now we know that an atom wants to complete its outer shell while keeping electrons in pairs of two now in A there are four electrons which which can be ejected while in B will want to accept 3 electrons to complete its shell as ejecting five will take lot of energy similar case will be for C,D and E which would want to accept 2,1,0 electrons respectively
Answer: Concentration of
at equilibrium = 0.08 M
Concentration of
at equilibrium =0.08 M
Concentration of
= 0.64M
Explanation:
Moles of
= 4.00 mole
Volume of solution = 5.00 L
Initial concentration of
=![\frac{moles}{Volume}=\frac{4.00mol}{5.00L}=0.8M](https://tex.z-dn.net/?f=%5Cfrac%7Bmoles%7D%7BVolume%7D%3D%5Cfrac%7B4.00mol%7D%7B5.00L%7D%3D0.8M)
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as ![K_c](https://tex.z-dn.net/?f=K_c)
For the given chemical reaction:
![2HI(g)\rightarrow H_2(g)+I_2(g)](https://tex.z-dn.net/?f=2HI%28g%29%5Crightarrow%20H_2%28g%29%2BI_2%28g%29%20)
Initial conc. 0.8 M 0 M 0 M
At eqm. conc. (0.8-2x) M (x) M (x) M
The expression for
is written as:
![K_c=\frac{[H_2]^1[I_2]^1}{[HI]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH_2%5D%5E1%5BI_2%5D%5E1%7D%7B%5BHI%5D%5E2%7D)
![0.016=\frac{(x)\times (x)}{(0.8-2x)}](https://tex.z-dn.net/?f=0.016%3D%5Cfrac%7B%28x%29%5Ctimes%20%28x%29%7D%7B%280.8-2x%29%7D)
![x=0.08M](https://tex.z-dn.net/?f=x%3D0.08M)
Concentration of
at equilibrium = x M = 0.08 M
Concentration of
at equilibrium = x M = 0.08 M
Concentration of
= (0.8-2x) = ![(0.8-2\times 0.08)M= 0.64M](https://tex.z-dn.net/?f=%280.8-2%5Ctimes%200.08%29M%3D%200.64M)