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Furkat [3]
3 years ago
15

Which alcohol will undergo acid-catalyzed dehydration under the mildest conditions?

Chemistry
1 answer:
damaskus [11]3 years ago
6 0
<span>Tertiary alcohols are the type of alcohols that will undergo acid-catalyzed dehydration under the mildest conditions. Types of tertiary alcohols are 2-methylpropan-2-ol and 2-methylbutan-2-ol. Other types of alcohols are referred to as primary alcohols and secondary alcohols.</span>
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How does the chemical formula for the nitrite ion differ from the chemical formula for the nitrate ion?
Darina [25.2K]
The nitrite ion has one less oxygen than the nitrate ion. Nitrate is NO3-1 while the nitrite ion is NO2-.
8 0
3 years ago
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Which would lower the reaction rate?
saveliy_v [14]

Answer:

D

Explanation: Decreasing the temperature of the system would lower the reaction rate.

4 0
3 years ago
For the following reaction, 6.94 grams of water are mixed with excess sulfur dioxide . Assume that the percent yield of sulfurou
Alexxx [7]
<h3>Answer:</h3>

#a. Theoretical yield = 31.6 g

#b. Actual yield = 25.72 g

<h3>Explanation:</h3>

The equation for the reaction between sulfur dioxide and water to form sulfurous acid is given by the equation;

SO₂(g) + H₂O(l) → H₂SO₃(aq)

The percent yield of H₂SO₃ is 81.4%

Mass of water that reacted is 6.94 g

#a. To get the theoretical yield of H₂SO₃ we need to follow the following steps

Step 1: Calculate the moles of water

Molar mass of water = 18.02 g/mol

Mass of water = 6.94 g

But, moles = Mass/molar mass

Moles of water = 6.94 g ÷ 18.02 g/mol

                        = 0.385 mol

Step 2: Calculate moles of H₂SO₃

From the equation, the mole ratio of water to H₂SO₃ is 1 : 1

Therefore, moles of water = moles of H₂SO₃

Hence, moles of H₂SO₃ = 0.385 mol

Step 3: Theoretical mass of H₂SO₃

Mass = moles × Molar mass

Molar mass of H₂SO₃ = 82.08 g/mol

Number of moles of H₂SO₃ = 0.385 mol

Therefore;

Theoretical mass of H₂SO₃ = 0.385 mol ×  82.08 g/mol

                                             = 31.60 g

Thus, the theoretical yield of H₂SO₃ is 31.6 g

<h3>#b. Calculating the actual yield</h3>

We need to calculate the actual yield

Percent yield of H₂SO₃ is 81.4%

Theoretical yield is 31.60 g

But; Percent yield = (Actual yield/theoretical yield)×100

Therefore;

Actual yield = Percent yield × theoretical yield)÷ 100

                   = (81.4 % × 31.6) ÷ 100

                  = 25.72 g

The percent yield of H₂SO₃ is 25.72 g

6 0
3 years ago
8.
Oksi-84 [34.3K]

Answer:

900 mg

Explanation:

4 0
3 years ago
Mr. Swerdlow wrote a chemical equation on the board and asked his class what should be changed to make it correct. He wrote:
Misha Larkins [42]

Answer is: 3. Water and carbon dioxide should both be moved to the products side, and glucose and oxygen should be moved to the reactants side.

Balanced chemical reaction for cellular respiration (convert biochemical energy):

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + energy, or:

glucose + oxygen → carbon dioxide + water + energy.

This reaction is exothermic (energy is released).

6 0
3 years ago
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