3 years ago

find the value of 10 times the square root of 2 over the square root of 5.. a. 2 b. 2 times the square root of 5. c. 2 the squar

e root of 10. d. 2 over 5 times the square root of 10.

1 answer:

6 0

$\dfrac{10\sqrt2}{\sqrt5}=\dfrac{10\sqrt2\cdot\sqrt5}{\sqrt5\cdot\sqrt5}=\dfrac{10\sqrt{2\cdot5}}{5}=\boxed{2\sqrt{10}}\to\fbox{c.}$

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3 years ago

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Grace [21]

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