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Anon25 [30]
3 years ago
14

5-13) -10-15 what’s the equation for the line that passes through points (5,-3) and (-10,15)

Mathematics
1 answer:
umka2103 [35]3 years ago
7 0

Answer: y=-6/5x+3

Step-by-step explanation:

To find the equation of the line that passes through the points, you want to first find the slope by using the formula m=\frac{y_2-y_1}{x_2-x_1}, then solve for the y-intercept.

m=\frac{15-(-3)}{-10-5} =\frac{18}{-15} =-\frac{6}{5}

Now that we have the slope, we can plug in a given point and solve for the y-intercept.

15=-6/5(-10)+b        [multiply]

15=12+b                   [subtract both sides by 12]

b=3

Now that we have the y-intercept, we know the equation is y=-6/5x+3.

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Answer:

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3 years ago
The equation of the graphed line in point-slope form is _______, and its equation in slope-intercept form is .
Ivenika [448]

Answer:

Point-slope form equation line

(y-3)=(-0.6)\times (x+2)

Slope-intercept form is:

y=-0.6x+1.8

Step-by-step explanation:

Point-slope form equation line passing through points (x_1,y_1)(x_2,y_2)

Slope = m  =\frac{y-2-y_1}{x_2-x_1}

slope-intercept form is:

y = mx +c

where : c = intercept of on axis

(y-y_1)=m\times (x-x_1)

Equation of line passing through (-2,3) and (3,0).

m=\frac{0-3}{3-(-2)}=-0.6

(y-3)=-0.6\times (x-(-2))

Point-slope form equation line

(y-3)=(-0.6)\times (x+2)

For slope-intercept form open the brackets of Point-slope form equation l:

y-3=-0.6x-1.2

So, the slope-intercept form is:

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7 0
3 years ago
What is the quadratic in vertex form that has an a value of 8 and a vertex of (5, 6)?
faltersainse [42]

Answer:

y= 8(x-5)² + 6

Step-by-step explanation:

Parabolas have two equation forms, namely; the standard and vertex form.

In the vertex form, y = a(x - h)² + k, the variables h and k are the coordinates of the parabola's vertex.

In this case; a=8, h =5, and k=6

Therefore;

The vertex equation will be

y= 8(x-5)² + 6

8 0
3 years ago
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