A process with a negative change in enthalpy and a negative change in entropy will generally be: <u>spontaneous</u>.
<h3>Gibbs free energy:</h3>
Since the Gibbs free energy is a parameter that tells us whether a chemical reaction is spontaneous (Gibbs free energy less than 0) or nonspontaneous (Gibbs free energy greater than 0) in this situation, we can describe it mathematically as:
ΔG = ΔH - TΔS
Therefore, any process with a negative change in enthalpy and a positive change in entropy will be spontaneous. If the enthalpy and the entropy are both negative, the subtraction becomes always negative, for which the Gibbs free energy is also negative.
One of the most crucial thermodynamic functions for the characterization of a system is the Gibbs free energy. It influences results like the voltage of an electrochemical cell and the equilibrium constant for a reversible reaction, among others.
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You do this one just like the other one that I just solved for you.
For this one ...
The density of the object is 2.5 gm/cm³.
We know that every cm³ of it we have contains 2.5 gm of mass.
We have to find out how many cm³ we have.
The question tells us: We have 2.0 cm³.
Each cm³ of space that the object occupies contains 2.5 gm of mass.
So the 2.0 cm³ that we have contains (2 x 2.5 gm) = 5 gms.
That's the mass of our object.
When a wave is too steep to support itself, the wave front collapses therefore creating a break.
<h3>What is a Wave?</h3>
This is defined as the propagation of disturbance from one place to another in an organized manner.
In situations where the wave is too steep to support itself there is a break in the wavefront which advances up the shoreline.
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Answer:
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The total gauge pressure at the bottom of the cylinder would
simply be the sum of the pressure exerted by water and pressure exerted by the
oil.
The formula for calculating pressure in a column is:
P = ρ g h
Where,
P = gauge pressure
ρ = density of the liquid
g = gravitational acceleration
h = height of liquid
Adding the two pressures will give the total:
P total = (ρ g h)_water + (ρ g h)_oil
P total = (1000 kg / m^3) (9.8 m / s^2) (0.30 m) + (900 kg /
m^3) (9.8 m / s^2) (0.4 - 0.30 m)
P total = 2940 Pa + 882 Pa
P total = 3,822 Pa
Answer:
The total gauge
pressure at the bottom is 3,822 Pa.