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3 years ago

PLEASE HELP DUE SOON

Mathematics

1 answer:

Ierofanga [76]3 years ago

7 0

Answer:

Train A's unit rate is 70 km per hour.

Train B's unit rate is 75 km per hour.

Train B is faster.

Step-by-step explanation:

Train A:

Distance traveled by train A is given as, $d=70t$

Where, $t$ is time in hours and $d$ is distance in kilometers.

Unit rate for train A is the distance traveled by it in 1 hour.

For t hours, distance traveled by train A = $70t$

∴ For, 1 hour, distance traveled by train A = $\frac{70t}{t}=70$ km per hour.

Therefore, unit rate for train A is 70 km/h.

Train B:

From the table,

Distance traveled in 2 hours = 150 km

∴ Distance traveled in 1 hour = $\frac{150}{2}=75$ km per hour.

Therefore, unit rate for train B is 75 km/h.

Speed is distance traveled per unit time.

Therefore, unit rate is nothing but speed of train.

As unit rate of train B is greater than that of train A, speed of train B is greater and thus faster.

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aivan3 [116]

Answer:

0.089

Step-by-step explanation:

f(x) = -ln(x) and g(x) = x²

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If we were to cut the region horizontally (perpendicular to the y-axis), the resulting line is the width of the square cross section. The thickness of this square is dy. So the volume of the square is:

dV = A dy

dV = s² dy

dV = (x₂ − x₁)² dy

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V = ∫ dV

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Evaluate with a calculator:

V ≈ 0.089

3 0

3 years ago

A plane is flying at an altitude of 17,000 feet. The angle of depression from the plane to the airport on the ground is 21°. Wha

viva [34]

Answer:

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Step-by-step explanation:

Using the SOH CAH TOA identity

Height of the plane = opposite = 17000feet

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Since Sin theta = opp/hyp

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x = 17000/sin21

x = 17000/0.3584

x = 47,433.0

Hence the distance between the plane and the airport to the nearest 10th of a foot is 47,433.0 feet

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3 years ago

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Answer:

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If we compare this function with the vertex form we see that:

$a=-1, h =-4, k = 2$

And since the value for a is negative we know that the parabola open downward. We don't have a minimum defined since open downwards and the maximum point correspond to the vertex on this case (-4,2).

Step-by-step explanation:

We need to remember that the standard form for a parabola is given by the following equation:

$y = ax^2 + bx +c$

And the vertex form is given by this formula:

$y = a(x-h)^2 +k$

And we want to find the vertex and if we have a maximum or minimum for each function. Let's begin with g(x)

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If we compare this function with the vertex form we see that:

$a = 1, h =2, k =-2$

So then the vertex would be $(h,k)=(2,-2)$

And since the value for a is positive we know that the parabola open upward. We don't have a maximum defined since open upwards and the minimum point correspond to the vertex on this case (2,-2).

For the function f(x) we assume that we have the following equation:

$f(x)= -(x+4)^2 +2$

If we compare this function with the vertex form we see that:

$a=-1, h =-4, k = 2$

And since the value for a is negative we know that the parabola open downward. We don't have a minimum defined since open downwards and the maximum point correspond to the vertex on this case (-4,2).

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3 years ago

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pochemuha

Answer:

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