(23.1 + 5.61 + 1.008) × 7.6134 × 8.431
= 29.718 × 7.6134 × 8.431
=1907.55608
The equation is solved in the manner that the term in the bracket is added first then mutiplication is done as according to Bodmas rule, if an equation contains brackets that need to be solved first then other operation that is division,multiplication, addition and subtraction are performed from left to right .
The electron group arrangement of PH₃ is tetrahedral. The molecular shape is a Trigonal pyramid, and the bond angle is 93°.
<h3>What is the bond angle?</h3>
The angle between the atoms in a compound is known as the bond angle. The degree of the binding angle is specified. There is also the bond length. It is the separation between the two atoms' nuclei.
The bond angle between the atoms of phosphine is 93°. It has one lone pair. The central atom is covered with 4 atoms.
Thus, the electron-group arrangement of phosphine is tetrahedral. The molecular geometry or shape is a trigonal pyramid. The bond angle is 93°.
To learn more about bond angles, refer to the link:
brainly.com/question/1851495
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Answer:
Pressure = 1.14 atm
Explanation:
Hello,
This question requires us to calculate the final pressure of the bottle after thermal equilibrium.
This is a direct application of pressure law which states that in a fixed mass of gas, the pressure of a given gas is directly proportional to its temperature, provided that volume remains constant.
Mathematically, what this implies is
P = kT k = P / T
P1 / T1 = P2 / T2 = P3 / T3 =........= Pn / Tn
P1 / T1 = P2 / T2
P1 = 1.0atm
T1 = -15°C = (-15 + 273.15)K = 258.15K
P2 = ?
T2 = 21.5°C = (21.5 + 273.15)K = 294.65K
P1 / T1 = P2 / T2
P2 = (P1 × T2) / T1
P2 = (1.0 × 294.65) / 258.15
P2 = 1.14atm
The pressure of the gas after attaining equilibrium is 1.14atm
The answer for the following problem is mentioned below.
<u><em>Therefore volume occupied by methane gas is 184.78 × 10^-3 liters </em></u>
Explanation:
Given:
mass of methane(
) = 272 grams
pressure (P) = 250 k Pa =250×10^3 Pa
temperature(t) = 54°C =54 + 273 = 327 K
Also given:
R = 8.31JK-1 mol-1 ,
Molar mass of methane() = 16.0 grams
We know;
According to the ideal gas equation,
<u><em>P × V = n × R × T</em></u>
here,
n = m÷M
n =272 ÷ 16
<u><em>n = 17 moles</em></u>
Therefore,
250×10^3 × V = 17 × 8.31 × 327
V = ( 17 × 8.31 × 327 ) ÷ ( 250×10^3 )
V = 184.78 × 10^-3 liters
<u><em>Therefore volume occupied by methane gas is 184.78 × 10^-3 liters </em></u>
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