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professor190 [17]
3 years ago
5

Covert 0.200 moles of H2SO4 to grams. Show all work

Chemistry
1 answer:
xxTIMURxx [149]3 years ago
3 0

Answer:

1. 19.6 g

2. 5.71 moles

3. 11.1 moles

Explanation:

In order to convert the moles to grams, either the grams to moles we need the molar mass of the compounds:

  • H₂SO₄ → 98 g/mol
  • H₂O → 18 g/mol

Let's make the conversions:

1. 0.2 mol . 98g / 1 mol = 19.6 g

2. 102.8 g . 1 mol / 18 g = 5.71 moles

3. 200 g . 1 mol / 18 g =  11.1 moles

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A pure compound is found to be 40.0% carbon by mass, 6.73% hydrogen by mass, and 53.3% oxygen by mass. determine the empirical f
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Since there is no weight, I would assume that this is a 100g of pure compound.
Okay so I would be changing the percentage to gram to solve for the mole.
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Comment Both propane and benzene are hydrocarbons. As a rule,
kozerog [31]

The enthalpy change : -196.2 kJ/mol

<h3>Further explanation  </h3>

The change in enthalpy in the formation of 1 mole of the elements is called enthalpy of formation  

The enthalpy of formation measured in standard conditions (25 ° C, 1 atm) is called the standard enthalpy of formation (ΔHf °)  

(ΔH) can be positive (endothermic = requires heat) or negative (exothermic = releasing heat)  

The value of ° H ° can be calculated from the change in enthalpy of standard formation:  

∆H ° rxn = ∑n ∆Hf ° (product) - ∑n ∆Hf ° (reactants)  

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∆H ° rxn = 2. ∆Hf ° H₂O - 2. ∆Hf °H₂O₂

\tt \Delta H_{rxn}=2.(-285.8)-2.(-187.8)\\\\\Delta H_{rxn}=-571.6+375.4=-196.2~kJ/mol\rightarrow \Delta Hf~O_2=0

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3 years ago
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