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3 years ago

What conditions would have to exist in order for a space station to support life

Physics

1 answer:

amid [387]3 years ago

4 0

Answer:

Mechanical life support system

Explanation:

Mechanical life support system is one which allows humans to survive on places or conditions which are not natural to their survival so by the help of mechanical devices humans can survive in places like underwater or in space.

The life support system may not only provide water, air and food but it should also keep a proper check on the maintenance of body pressure, temperature, management of the waste product and the absorption or the radiations from the body itself.

Thus mechanical life support system are designed with the hep of high engineering techniques for the safety and security as these are life-critical.

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A normal walking speed is around 2.0 m/s . how much time t does it take the box to reach this speed if it has the acceleration 5

creativ13 [48]

Given:

u(initial velocity)=0

a=5.54m/s^2

v(final velocity)=2 m/s

v=u +at

Where v is the final velocity.

u is the initial velocity

a is the acceleration.

t is the time

2=0+5.54t

t=2/5.54

t=0.36 sec

6 0

3 years ago

A conservative force does the same work regardless of the path taken.

ella [17]

A conservative force is a force that when work is done against this force the work done does not depend on the path taken only the initial and final position.

5 0

3 years ago

Read 2 more answers

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: =E−Ryn2 In this equation Ry stands for

skelet666 [1.2K]

Answer:

λ = 162 10⁻⁷ m

Explanation:

Bohr's model for the hydrogen atom gives energy by the equation

$E_{n}$ = - k²e² / 2m (1 / n²)

Where k is the Coulomb constant, e and m the charge and mass of the electron respectively and n is an integer

The Planck equation

E = h f

The speed of light is

c = λ f

E = h c /λ

For a transition between two states we have

$E_{n}$ - $E_{m}$ = - k²e² / 2m (1 / $n_{f}$ ² -1 / $n_{i}$ ²)

h c / λ = -k² e² / 2m (1 / $n_{f}$ ² - 1/ $n_{i}$ ²)

1 / λ = (- k² e² / 2m h c) (1 / $n_{f}$ ² - 1/ $n_{i}$ ²)

The Rydberg constant with a value of 1,097 107 m-1 is the result of the constant in parentheses

Let's calculate the emission of the transition

1 /λ = 1.097 10⁷ (1/10² - 1/8²)

1 / λ = 1.097 10⁷ (0.01 - 0.015625)

1 /λ = 0.006170625 10⁷

λ = 162 10⁻⁷ m

3 0

3 years ago

Is being a plat 2 in rainbow 6 siege a good rank?

icang [17]

Answer:

In a way it does, but overall, there are many factors that affect your rank. In general, and talking about the average Platinum II, they are pretty decent according to casual player standards.

Explanation:

6 0

3 years ago

It is measured that 3/4 of a body's volume is submerged in oil of density 800kg/m³

Evgesh-ka [11]

Complete question:

It is measured that 3/4 of a body's volume is submerged in oil of density 800kg/m³. What is the specific gravity of oil?

Answer:

The specific gravity of the oil is 0.8.

Explanation:

Given;

density of the oil, $\rho_o$ = 800 kg/m³

density of water, $\rho_w$ = 1000 kg/m³

The specific gravity of any substance is the ratio of the substance density to the density of water.

Specific gravity of the oil = density of the oil / density of water

Specific gravity of the oil = 800/1000

Specific gravity of the oil = 0.8

Therefore, the specific gravity of the oil is 0.8.

8 0

3 years ago