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pishuonlain [190]
3 years ago
6

A cart of mass 6.0 kg moves with a speed of 3.0 m/s towards a second stationary cart with a mass of 3.0 kg. The carts move on a

frictionless surface and when the carts collide they stick together. What is the ratio of the initial kinetic energy of the two-cart system to the final kinetic energy of the two-cart system?
a. 2
b. 1.5
c. 2.5
d. 1.25
e. 3
Physics
1 answer:
katen-ka-za [31]3 years ago
6 0

Answer:b

Explanation:

Given

mass of first cart m_1=6 kg

mass of second cart m_2=3 kg

velocity of first cart v_1=3 m/s

conserving momentum

m_1v_1+m_2v_2=(m_1+m_2)v

6\times 3+3\times 0=(9)\cdot v

v=2 m/s

Initial kinetic Energy K.E._1=\frac{1}{2}m_1v_1^2+\frac{1}{2}m_2v_2^2

K.E._1=\frac{1}{2}\cdot 6\cdot 3^2+0

K.E._1=27 J

Final Kinetic Energy

K.E._2=\frac{1}{2}(m_1+m_2)v^2

K.E._2=\frac{1}{2}(6+3)\cdot 2^2=18 J

Ratio of initial Kinetic Energy to the Final Kinetic Energy

=\frac{27}{18}=1.5

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Learn more about net force and Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

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