Answer:
Explanation:
Given
Distance between two loud speakers ![d=1.6\ m](https://tex.z-dn.net/?f=d%3D1.6%5C%20m)
Distance of person from one speaker ![x_1=3\ m](https://tex.z-dn.net/?f=x_1%3D3%5C%20m)
Distance of person from second speaker ![x_2=3.5\ m](https://tex.z-dn.net/?f=x_2%3D3.5%5C%20m)
Path difference between the waves is given by
![x_2-x_1=(2m+1)\cdot \frac{\lambda }{2}](https://tex.z-dn.net/?f=x_2-x_1%3D%282m%2B1%29%5Ccdot%20%5Cfrac%7B%5Clambda%20%7D%7B2%7D)
for destructive interference m=0 I.e.
![x_2-x_1=\frac{\lambda }{2}](https://tex.z-dn.net/?f=x_2-x_1%3D%5Cfrac%7B%5Clambda%20%7D%7B2%7D)
![3.5-3=\frac{\lambda }{2}](https://tex.z-dn.net/?f=3.5-3%3D%5Cfrac%7B%5Clambda%20%7D%7B2%7D)
![\lambda =0.5\times 2](https://tex.z-dn.net/?f=%5Clambda%20%3D0.5%5Ctimes%202)
![\lambda =1\ m](https://tex.z-dn.net/?f=%5Clambda%20%3D1%5C%20m)
frequency is given by
![f=\frac{v}{\lambda }](https://tex.z-dn.net/?f=f%3D%5Cfrac%7Bv%7D%7B%5Clambda%20%7D)
where ![v=velocity\ of\ sound\ (v=343\ m/s)](https://tex.z-dn.net/?f=v%3Dvelocity%5C%20of%5C%20sound%5C%20%28v%3D343%5C%20m%2Fs%29)
![f=\frac{343}{1}=343\ Hz](https://tex.z-dn.net/?f=f%3D%5Cfrac%7B343%7D%7B1%7D%3D343%5C%20Hz)
For next frequency which will cause destructive interference is
i.e.
and ![m=2](https://tex.z-dn.net/?f=m%3D2)
![3.5-3=\frac{2\cdot 1+1}{2}\cdot \lambda](https://tex.z-dn.net/?f=3.5-3%3D%5Cfrac%7B2%5Ccdot%201%2B1%7D%7B2%7D%5Ccdot%20%5Clambda)
![\lambda =\frac{1}{3}\ m](https://tex.z-dn.net/?f=%5Clambda%20%3D%5Cfrac%7B1%7D%7B3%7D%5C%20m)
frequency corresponding to this is
![f_2=\frac{343}{\frac{1}{3}}=1029\ Hz](https://tex.z-dn.net/?f=f_2%3D%5Cfrac%7B343%7D%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D1029%5C%20Hz)
for ![m=2](https://tex.z-dn.net/?f=m%3D2)
![3.5-3=\frac{5}{2}\cdot \lambda](https://tex.z-dn.net/?f=3.5-3%3D%5Cfrac%7B5%7D%7B2%7D%5Ccdot%20%5Clambda%20)
![\lambda =\frac{1}{5}\ m](https://tex.z-dn.net/?f=%5Clambda%20%3D%5Cfrac%7B1%7D%7B5%7D%5C%20m)
Frequency corresponding to this wavelength
![f_3=\frac{343}{\frac{1}{5}}](https://tex.z-dn.net/?f=f_3%3D%5Cfrac%7B343%7D%7B%5Cfrac%7B1%7D%7B5%7D%7D)
The maximum velocity in a banked road, ignoring friction, is given by;
v = Sqrt (Rg tan ∅), where R = Radius of the curved road = 2*1000/2 = 1000 m, g = gravitational acceleration = 9.81 m/s^2, ∅ = Angle of bank.
Substituting;
30 m/s = Sqrt (1000*9.81*tan∅)
30^2 = 1000*9.81*tan∅
tan ∅ = (30^2)/(1000*9.81) = 0.0917
∅ = tan^-1(0.0917) = 5.24°
Therefore, the road has been banked at 5.24°.
Answer:
because solar enegry is a perpetual source of enegry and by using it non renewable sources of enegry can be preserved and also prevents from enegry crisis.
hope its helpful to uh
Answer:
Given,
mass of man = 100 N = 10 kg
height = h = 25m
since the man does not move anything with his force, work done by him is zero
work done on the man = gain in potential energy
P.E=mgh
P.E=10×9.8×25
P.E=2.45KJ
Explanation:
so, potential energy gained by man is 2.45 KJ
Fine, lets do a retry of this.
Δd = -0.9m
v₁ = 0
v₂ = ?
a = -9.8 m/s²
Δt = ?
We can use the following kinematic equation and solve for Δt.
Δd = v₁Δt + 0.5(a)(Δt)²
Δd = 0.5(a)(Δt)²
2Δd = a(Δt)²
√2Δd/a = Δt
√2(-0.9m)/(-9.8 m/s²) = Δt
0.<u>4</u>28571428574048 = Δt
Therefore, it takes 0.4 seconds for the glass to hit the ground, or 0.43s as you said (even though I don't believe it follows significant digit rules)